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10 square feet

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โˆ™ 2012-10-15 20:12:02
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Two nonadjacent angles formed by two intersecting lines are what angles

What is the sum of the interior angle measures of a 15-gon

What would be the area of a regular polygon with a perimeter of 30 feet and an apothem of 4 feet

If a 2 cm and r 3.4 cm find the area of the regular pentagon Round the answer to one decimal place

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Q: What would be the area of a regular polygon with a perimeter of 10 feet and an apothem of 2 feet?
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Related questions

What would be the area of a regular polygon with a perimeter of 10 feet and an apothem of 14 feet?

Such a polygon is not possible.


What would be the area of a regular polygon with a perimeter of 30 feet and an apothem of 4 feet?

60ft


What would be the area of a regular polygon with a perimetr of 30ft and an apothem of 4ft?

The area of a regular polygon is equal to one-half the product of the apothem and the perimeter. 40x30 divided by 2=600 square feet


What would be the area of a regular polygon with the perimeter of 10 feet and an apothem of 2 feet?

The answer will depend on the number of sides in the polygon. Since that information is not given, there can be no answer.


A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of what?

An apothem of a regular polygon is a segment from its center to the midpoint of a side. You can use the apothem to find the area of a regular polygon using this formula: A = pa/2 where p is the perimeter of the figure and a is the apothem. For a regular octagon with side length 11, the perimeter p = 8(11) = 88. So the area would be A = 88(8.85)/2 = 389.4 square units.


What would be the area of a regular polygon with a perimeter of 10 feet and the apothem of 2 feet?

Area of regular polygon: 0.5*2*10 = 10 square feet


What would be the area of a regular polygon with the perimeter of 20 ft and apothem of 3 ft?

Area of regular polygon: 0.5*20*3 = 30 square feet


What would be the area of a polygon with a perimeter of 30 feet and a apothem of 4 feet?

60ft


What would be the area of a regular polygon with a 20 feet and an apothem of 3 feet?

the formula for a regular polygon is A=1/2(apothem)(perimeter). So, first you would do 1/2 times 3 which equals 3/2. 3/2 times 20 is 30. so 30 is the area.


What would be the area of a regular polygon with a perimeter of 20 feet and and apothem of 3 feet?

30ft * * * * * No, it is 30 SQUARE feet. Area cannot be measured in feet!


What would be the area of a regular polygon with a perimeter of 20 feet and an apothem of 3 feet?

30ft * * * * * No, it is 30 SQUARE feet. Area cannot be measured in feet!


What would be the area or a regular polygon with a perimeter of 20 feet and an apoyhem of 3 feet?

The formula for finding the area (A) of a regular polygon when its perimeter (p) and apothem (a) are known is: A=(pa)/2 Therefore, when the figures are put into the formula it becomes: A=(20 x 3)/2 A=60/2 A=30 square feet

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