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What would be the area of a regular polygon with the perimeter of 20 ft and apothem of 3 ft?
Wiki User
∙ 6y ago
Area of regular polygon: 0.5*20*3 = 30 square feet
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoThe answer will depend on the number of sides in the polygon. Since that information is not given, there can be no answer.
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What would be the area of a regular polygon with a perimeter of 30 feet and and apothem of 4 feet?
60ft
What would be the area of a regular polygon with a perimetr of 30ft and an apothem of 4ft?
The area of a regular polygon is equal to one-half the product of the apothem and the perimeter. 40x30 divided by 2=600 square feet
What would be the area of a regular polygon with the perimeter of 10 feet and an apothem of 2 feet?
The answer will depend on the number of sides in the polygon. Since that information is not given, there can be no answer.
What would be the area of a regular polygon with a 20 feet and an apothem of 3 feet?
the formula for a regular polygon is A=1/2(apothem)(perimeter). So, first you would do 1/2 times 3 which equals 3/2. 3/2 times 20 is 30. so 30 is the area.
What would be the area or a regular polygon with a perimeter of 20 feet and an apoyhem of 3 feet?
The formula for finding the area (A) of a regular polygon when its perimeter (p) and apothem (a) are known is: A=(pa)/2 Therefore, when the figures are put into the formula it becomes: A=(20 x 3)/2 A=60/2 A=30 square feet
What would be the area of a regular polygon with a perimeter of 10 feet and an apothem of 14 feet?
Such a polygon is not possible.
What would be the area of a regular polygon with a perimeter of 30 feet and an apothem of 4 feet?
60ft
What would be the area of a regular polygon with a perimeter of 30 feet and and apothem of 4 feet?
60ft
What would be the area of a regular polygon with a perimetr of 30ft and an apothem of 4ft?
The area of a regular polygon is equal to one-half the product of the apothem and the perimeter. 40x30 divided by 2=600 square feet
What would be the area of a regular polygon with a perimeter of 10 feet and an apothem of 2 feet?
10 square feet
What would be the area of a regular polygon with the perimeter of 10 feet and an apothem of 2 feet?
The answer will depend on the number of sides in the polygon. Since that information is not given, there can be no answer.
A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of what?
An apothem of a regular polygon is a segment from its center to the midpoint of a side. You can use the apothem to find the area of a regular polygon using this formula: A = pa/2 where p is the perimeter of the figure and a is the apothem. For a regular octagon with side length 11, the perimeter p = 8(11) = 88. So the area would be A = 88(8.85)/2 = 389.4 square units.
What would be the area of a regular polygon with a perimeter of 10 feet and the apothem of 2 feet?
Area of regular polygon: 0.5*2*10 = 10 square feet
What would be the area of a regular polygon with a 20 feet and an apothem of 3 feet?
the formula for a regular polygon is A=1/2(apothem)(perimeter). So, first you would do 1/2 times 3 which equals 3/2. 3/2 times 20 is 30. so 30 is the area.
What would be the area of a polygon with a perimeter of 30 feet and a apothem of 4 feet?
60ft
What would be the area of a regular polygon with a perimeter of 20 feet and and apothem of 3 feet?
30ft * * * * * No, it is 30 SQUARE feet. Area cannot be measured in feet!
What would be the area of a regular polygon with a perimeter of 20 feet and an apothem of 3 feet?
30ft * * * * * No, it is 30 SQUARE feet. Area cannot be measured in feet!
