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66, 68, 70 Check: 66+68=134, 134+76=210, 210/3=70 ; 66, 68, 70

Q: What would be three times the largest of three consecutive even integers is seventy six more than the sum of the other two integers?

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consecutive means following each other so 3,4,5 are consecutive as are; 100,101,102 etc

This is impossible, in mathematical terms. If you take two consecutive integers, then one of the integers must be odd and the other must be even. When you add an odd number to an even number, the result is always an odd number. Here, you said two consecutive integers add up to 26, which is an even number. Therefore, the answer is "No real solutions."

let largest number be x, other numbers are x-1,x-2 (since they are consecutive) now, it says x+(x-1) + (x-2)= 18 = 3x -3=18 = 3x= 18+3 = 3x= 21 = x= 21/3 = x= 7 therefore largest number is 7.

There are no two such consecutive 'integers'!!Proof: Let the first integer be x.So, the next consecutive integer is x+1.Now, as per the question : x + (x+1) = 24=> 2x=23 (After taking all constants on one side and variable terms on the other).=> x=(23/2) = 11.5So, 11.5 & 12.5 are the required numbers but they are not integers !

There is no set of three consecutive even integers whose sum is 999. There are two other sets; one is odd, the other is mixed. The odd set is 331, 333 and 335. The mixed set is 332, 333 and 334.

Related questions

"Consecutive" integers are integers that have no other integer between them.

There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.

There are no consecutive integers that add or multiply to 224. If you meant some other binary operation, you should specify what you meant.

consecutive means following each other so 3,4,5 are consecutive as are; 100,101,102 etc

Yes, the integers are 12 and 13.

You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.

There are no such numbers. If S is the sum of any 4 consecutive integers then S = 2 (mod 4) In other words, any four consecutive integers add up to an even number that is NOT dvisible by 4.

Consecutive integers mean the numbers follow one after the other. So, if you let x be an integer, then x, x+1, and x+2 are your three consecutive integers. "Sum" means they were added. So: x+(x+1)+(x+2)=237 => 3x+3 = 237 => 3x = 234 => x=78. Therefore, your integers are: 78, 79, and 80.

This is impossible, in mathematical terms. If you take two consecutive integers, then one of the integers must be odd and the other must be even. When you add an odd number to an even number, the result is always an odd number. Here, you said two consecutive integers add up to 26, which is an even number. Therefore, the answer is "No real solutions."

The larger is 114, and the other is 112.

No two consecutive EVEN integers sum to 124 since: Let x be the lowest of the two integers. Then the other integer is x+2 and x + (x+2) = 124 iff 2x = 122 iff x=61, an odd integer.

THere are two pair of consecutive integers. 52 = 25 < 30 < 36 = 62 So, one pair is 5 and 6 and the other pair is -6 and -5.