The two consecutive positive integers whose product is 380 are 19 x 20.
391x2
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
-10 -11
-8 -9
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
Two consecutive integers which multiply together to equal 156 are 12 and 13.
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.
There is no set of two consecutive integers having a product of 14. Product means the result of multiplication.
There is no set of two consecutive integers equating to 200.
No, it is not. It is the sum of two consecutive integers: 46 and 47.
The two consecutive positive integers whose product is 380 are 19 x 20.
There are no two consecutive integers, negative or positive, whose product is 440.
Their product is 143.
what is the formula to use to solve the product of two consecutive odd integers