6 feet...
area 24
perimeter 20
The length and width can't be determined since it is a rectangle. A length would need to be given, or it would have to be a square.
The area of a rectangle is length x width.
The area of the rectangle is 72 square feet
The width is 24 feet.
The width is 6 feet. The length is 8 feet.
The length is 7 feet and the width is 5 feet
Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
Area = length x width, so the area of this rectangle would be 15 feet x 9 feet which equals 135 square feet.
The width is 8 feet