Yes, quite easily.
Mean = 2. Variance = 1.
mean = 5, variance = 5
3/8
(0.5)n
The probability is 50-50.
The frequency can be determined by recording the sum for each toss and producing a tally chart for the outcomes.
The probability is 3/4.
It is 1/2^7 = 1/128.
mean = np = 20*0.5 = 10 Variance = npq = 20*0.5*0.5 = 5 Std dev = sqrt(npq) = sqrt(20*0.5*0.5) = 2.23
It is the event that one of the two coins lands showing tails and the other shows heads.
The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.
1/2 or 50% (1/8 prob of 0H + 3/8 prob of 1H)