mean = 5, variance = 5
mean = np = 20*0.5 = 10 Variance = npq = 20*0.5*0.5 = 5 Std dev = sqrt(npq) = sqrt(20*0.5*0.5) = 2.23
The probability of a heads is 1/2. The expected value of independent events is the number of runs times the probability of the desired result. So: 100*(1/2) = 50 heads
The expected value of the number of Heads in 1 toss of a fair coin is 0.5. So the expected number of Heads in 10000 tosses of a fair coin is ... 5000!
The probability of tossing two heads in two coins is 0.25.
(0.5)n
mean = np = 20*0.5 = 10 Variance = npq = 20*0.5*0.5 = 5 Std dev = sqrt(npq) = sqrt(20*0.5*0.5) = 2.23
thas so true
The probability of a heads is 1/2. The expected value of independent events is the number of runs times the probability of the desired result. So: 100*(1/2) = 50 heads
The number of sequences is 27 or 128.
Coins do not have numbers, there is only the probability of heads or tails.
The expected value of the number of Heads in 1 toss of a fair coin is 0.5. So the expected number of Heads in 10000 tosses of a fair coin is ... 5000!
Eight.
The odds are 50/50. A tossed coin does not have a memory.
In a series of ten coin tosses, each toss has two possible outcomes: heads or tails. The expected number of heads can be calculated as the product of the number of tosses and the probability of getting heads in a single toss, which is 0.5. Therefore, in ten tosses, the expected number of heads is 10 × 0.5 = 5 heads. However, the actual number of heads can vary due to the randomness of each toss.
The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.
It is 0.5
50%