Q: A fair coin is tossed 10 times what are the expected mean and variance of the number of heads?

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mean = np = 20*0.5 = 10 Variance = npq = 20*0.5*0.5 = 5 Std dev = sqrt(npq) = sqrt(20*0.5*0.5) = 2.23

The probability of a heads is 1/2. The expected value of independent events is the number of runs times the probability of the desired result. So: 100*(1/2) = 50 heads

The expected value of the number of Heads in 1 toss of a fair coin is 0.5. So the expected number of Heads in 10000 tosses of a fair coin is ... 5000!

The probability of tossing two heads in two coins is 0.25.

(0.5)n

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mean = np = 20*0.5 = 10 Variance = npq = 20*0.5*0.5 = 5 Std dev = sqrt(npq) = sqrt(20*0.5*0.5) = 2.23

thas so true

The probability of a heads is 1/2. The expected value of independent events is the number of runs times the probability of the desired result. So: 100*(1/2) = 50 heads

The number of sequences is 27 or 128.

Coins do not have numbers, there is only the probability of heads or tails.

The expected value of the number of Heads in 1 toss of a fair coin is 0.5. So the expected number of Heads in 10000 tosses of a fair coin is ... 5000!

Eight.

The odds are 50/50. A tossed coin does not have a memory.

The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.

50%

It is 0.5

It means that if the coin were tossed an infinite number of times, half of the tosses would come up heads and half would be tails.