Always 2
false
If 39 had any even factor then that 39 would be a multiple of an even factor. Therefore, 39 would be a multiple of 2 and so 39 would be even. It is not and so all factors of 39 are odd.
They are not. The factors of 6 are 1, 2, 3, 6. Two odd, two even. Maybe you mean multiples of 6? These are all even because 6 = 2x3 and any multiple of 6 is a multiple of 2 so will be even.
Every number is a multiple of its factors. That's what "factors" means. Surprise !
It is a multiple of any of its factors
75 is a multiple of 5 that has 6 factors.
Yes, because every integer is a multiple of its factors.
A multiple, by definition, is a number that another number can be multiplied to get. For instance, since 2 x 3 = 12, 12 is a multiple of both 2 and 3. A factor is the opposite. For instance, since 2 x 3 = 12, both 2 and 3 are factors of 12. Multiples and factors have everything to do with multiplication. Multiple is even the base word for multiplication.
No number will produce only odd multiples, as any multiple of an even number will always be even. Proofs can be easily created of such a fact.
It is a multiple of its factors. These are 1,2,3,5,6,10,15,25,30,50,75 and 150.
An even number can be a multiple of an odd number OR an even number. An odd number cannot be a multiple of an even number.
No, it is not possible. Every multiple of 21 is a composite number. 21 is a composite number and its factors are 1, 3, 7 and 21(4 factors). Any multiple of 21 must have all the factors of 21. So, every multiple of 21 has at least 4 factors. And a prime number has only two factors so, any multiple of 21 can't be prime.