Let n be the number, then :
(1) (a x 13) +11 = n, and
(2) (b x 17) + 9 = n, therefore
13a + 11 = 17b + 9 : 13a + 2 = 17b
This equation holds true when a = 9, when 117 + 2 = 119 = 17 x 7, so b = 7
Substituting for a in Equation (1) : n = (9 x 13) + 11 = 117 + 11 = 128
Substituting for b in Equation (2) : n = (7 x 17) + 9 = 119 + 9 = 128
The required number is 128.
11
the remainder of the given number when divided by 7
8.
154
139
It will be 3.
141, 349, 557, 765, 973, etc...
85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11
11
Divide each of these numbers by 11, and the remainder is 5.
8.
the remainder of the given number when divided by 7
11.5
154
It is: 137/12 = 11 with a remainder of 5
Because there is a remainder when it is divided by 2
139