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Let n be the number, then :

(1) (a x 13) +11 = n, and

(2) (b x 17) + 9 = n, therefore

13a + 11 = 17b + 9 : 13a + 2 = 17b

This equation holds true when a = 9, when 117 + 2 = 119 = 17 x 7, so b = 7

Substituting for a in Equation (1) : n = (9 x 13) + 11 = 117 + 11 = 128

Substituting for b in Equation (2) : n = (7 x 17) + 9 = 119 + 9 = 128

The required number is 128.

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โˆ™ 14y ago
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Q: When a number is divided by 13 the remainder is 11 when the same number is divided by 17 the remainder is 9 what is the number?
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