121
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
121
8 times with a remainder of 1
121
121
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
121
121
121 divided by 3 equals 40 with a remainder of 1.
121 divided by 6 equals 20 with a remainder of 1.
11 divide by 2 is 5 remainder 1 5 divided by 2 is 2 remainder 2 2 divided by 2 is 1 the answear is 121 correct me if am wrong?
121!
121
121.5
121.25
No, it depends on divided WHAT!