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Replace "not" with "1" and you have a true statement.

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0#include<iostream> #include<array> #include<sstream> std::array<int,10> get_frequency (int range_min, int range_max) { if (range_max<range_min) std::swap (range_min, range_max); std::array<int,10> digit {}; for (int count {range_min}; count<=range_max; ++count) { std::stringstream ss {}; ss << count; std::string s {}; ss >> s; for (auto c : s) { ++digit[c-'0']; } } return digit; } int main () { std::array<int,10> digit {}; digit = get_frequency(1, 89); std::cout << "In the range 1 to 89...\n"; for (int d {0}; d<10; ++d) { std::cout << "\tthe digit " << d << " appears " << digit[d] << " times.\n"; } } Output: In the range 1 to 89... the digit 0 appears 8 times. the digit 1 appears 19 times. the digit 2 appears 19 times. the digit 3 appears 19 times. the digit 4 appears 19 times. the digit 5 appears 19 times. the digit 6 appears 19 times. the digit 7 appears 19 times. the digit 8 appears 19 times. the digit 9 appears 9 times.

The digit 1 appears 301 times, as opposed to 300 for the digits 2 to 9.

10 times for the one's digit, 1-100 10 times for the ten's digit, 60-70 = 20 times

It appears 20 times.

Assuming you mean in the numbers 1, 2, 3, ..., 998, 999, 1000 then the digit 0. (The digit 1 appears 301 times, the digits 2-9 all appear 300 times each, but the digit 0 only appears 192 times.)

As a digit in other numbers it appears 20 times

In a 500 page book the digit 1 appears 200 times

In the King James version the word - written - appears 277 times and the word - Write - appears 91 times the word - writer - appears twice the word - writer's - appears twice the word - writest - appears twice the word - writeth - appears once the word - writing - appears 38 times the word - writings - appears once

It appears 25 times.

In the King James version the word - written - appears 277 times and the word - Write - appears 91 times the word - writer - appears twice the word - writer's - appears twice the word - writest - appears twice the word - writeth - appears once the word - writing - appears 38 times the word - writings - appears once

In the King James Version of the Bible, the word "help" appears 166 times. "helped" appears 25 times, "helper" appears 16 times, "helpers" appears 7 times, "helpeth" appears 4 times, "helping" appears 3 times, and "helps" appears twice.

Assuming you are asking how many times the digit 1 appears when writing the numbers 400 to 500: It appears in the tens place once (41x where x is any digit 0-9) so there will be 10 occurrences of it here. It appears in the ones place for every digit in the tens place (4x1) so there will be 10 occurrences of it here. However, the number 411 has been counted twice, once as 41x and again as 4x1. Thus the digit 1 will be written 10 + 10 - 1 = 19 times.

Zero. It appears only 10 times, all the others 20 times.

Very interesting !No.In all of the 3-digit numbers ... 100 - 999 ... each of the digits 1 - 9 appears 190 times,but zero appears 990 times.

The digit 3 will be written 20 times.

87 and 331000 are two integers. they are expressed as decimals which is a way of representing numbers so that the place value of each digit is ten times that of the digit to its right.

In the King James version the word - heaven - appears 582 times the word - heaven's - appears once the word - heavenly - appears 23 times the word - heavens - appears 133 times

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