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The digit 1 appears 301 times, as opposed to 300 for the digits 2 to 9.

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Q: Which Digit Appears The Most 1 to 1000?
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What digit does appear most frequently between numbers 1 and 1000?

By including the number 1000, the digit 1.


What digit is the least frequent between the number 1 and 1000?

Assuming you mean in the numbers 1, 2, 3, ..., 998, 999, 1000 then the digit 0. (The digit 1 appears 301 times, the digits 2-9 all appear 300 times each, but the digit 0 only appears 192 times.)


Which digit 0 - 9 appears least number of times between 1 and 1000?

9


What digit is the most frequent between the numbers 1 and 1000?

1-301 times


How many times does the digit 9 appears from 1 to 1000?

The digit 9 appears in the units place 100 times from 1 to 1000 (9, 19, 29,..., 989, 999). It also appears in the tens place 100 times (90, 91, 92,..., 99, 190, 191,..., 199, 290,..., 999). Therefore, the digit 9 appears a total of 200 times from 1 to 1000.


How many the digit 3 appears in numbers from 1to100?

The digit appears eleven time from 1 to 100.


How many 3 digit whole numbers are there between 1 and 1000?

There are 900 three-digit whole numbers between 1 and 1000


In any 24 hour period of time what digit appears most on a digital clock?

1


How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?

How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?


How many positive four digit integers have 1 as their first digit and 2 or 5 as their last digit?

There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.


What is the program to figure out how many numbers from 0 to 9 are needed for 1 to 89 for example?

#include<iostream> #include<array> #include<sstream> std::array<int,10> get_frequency (int range_min, int range_max) { if (range_max<range_min) std::swap (range_min, range_max); std::array<int,10> digit {}; for (int count {range_min}; count<=range_max; ++count) { std::stringstream ss {}; ss << count; std::string s {}; ss >> s; for (auto c : s) { ++digit[c-'0']; } } return digit; } int main () { std::array<int,10> digit {}; digit = get_frequency(1, 89); std::cout << "In the range 1 to 89...\n"; for (int d {0}; d<10; ++d) { std::cout << "\tthe digit " << d << " appears " << digit[d] << " times.\n"; } } Output: In the range 1 to 89... the digit 0 appears 8 times. the digit 1 appears 19 times. the digit 2 appears 19 times. the digit 3 appears 19 times. the digit 4 appears 19 times. the digit 5 appears 19 times. the digit 6 appears 19 times. the digit 7 appears 19 times. the digit 8 appears 19 times. the digit 9 appears 9 times.


What is the predecessor of the smallest 4 digit number?

Predecessor of a number is obtained by subtracting 1 from it. The smallest 4 digit number is 1000 and its predecessor is 1000 - 1 = 999.