The digit 1 appears 301 times, as opposed to 300 for the digits 2 to 9.
Assuming you mean in the numbers 1, 2, 3, ..., 998, 999, 1000 then the digit 0. (The digit 1 appears 301 times, the digits 2-9 all appear 300 times each, but the digit 0 only appears 192 times.)
1-301 times
When rounding numbers, we typically look at the digit immediately to the right of the rounding digit. In this case, the digit to the right of 9 is 9, which is greater than or equal to 5. When the digit to the right is 5 or greater, we round the rounding digit up by 1. Therefore, 996 is rounded up to 1000.
300
All the numbers between 999 and 3000 are four-digit numbers. You need to subtract 3000 - 999 - 1. The extra -1 is to account for the fact that the numbers 999 and 3000, in this case, are not included.
By including the number 1000, the digit 1.
Assuming you mean in the numbers 1, 2, 3, ..., 998, 999, 1000 then the digit 0. (The digit 1 appears 301 times, the digits 2-9 all appear 300 times each, but the digit 0 only appears 192 times.)
9
To find how many sevens there are from 1 to 1000, we can consider the occurrences of the digit '7' in each digit place (hundreds, tens, and units). In the range from 1 to 999, the digit '7' appears 300 times: 100 times in each of the hundreds, tens, and units places. Including the number 1000, which has no sevens, the total remains 300. Thus, there are 300 occurrences of the digit '7' from 1 to 1000.
1-301 times
To determine how many times the digit 9 is written when writing numbers from 1 to 10000, we can consider the pattern of its occurrence in each place value. In the units place, the digit 9 appears 1000 times (from 9 to 9999). In the tens place, the digit 9 appears 1000 times (from 90 to 99, 190 to 199, and so on). In the hundreds place, the digit 9 appears 1000 times (from 900 to 999, 1900 to 1999, and so on). Therefore, the digit 9 is written 3000 times in total when writing numbers from 1 to 10000.
The digit 9 appears in the units place 100 times from 1 to 1000 (9, 19, 29,..., 989, 999). It also appears in the tens place 100 times (90, 91, 92,..., 99, 190, 191,..., 199, 290,..., 999). Therefore, the digit 9 appears a total of 200 times from 1 to 1000.
The digit appears eleven time from 1 to 100.
To find how many times the digit '9' appears from 1 to 1000, we can analyze the occurrences in each digit place: hundreds, tens, and units. In the hundreds place, '9' appears in the range 900-999, contributing 100 occurrences. In the tens place, it appears in the sequences 90-99, 190-199, ..., 990-999, totaling 100 occurrences across those ranges. Lastly, in the units place, it appears in sequences like 9, 19, 29, ..., 999, which also adds up to 100 occurrences. Therefore, the total count of the digit '9' from 1 to 1000 is 300.
There are 900 three-digit whole numbers between 1 and 1000
1
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?