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There are 50 multiples of 80 between 1 and 4000, as 4000 divided by 80 equals 50. However, the question asks for the number of occurrences of the digit "8" in the range from 1 to 4000, not the number of multiples of 80. The digit "8" appears in the units place for numbers 8, 18, 28, ..., 3998, occurring 500 times. Additionally, it appears in the tens place for numbers 80, 81, ..., 89, 180, 181, ..., 189, and so on, occurring 400 times. Therefore, the digit "8" appears 900 times in the range from 1 to 4000.
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There are 9 single digits (1, 2, 3, 4, 5, 6, 7, 8, 9) that are repeated throughout the numbers from 1 to 1000000. Each single digit appears 100,000 times (except for 0, which appears 100,000 times as well). Therefore, there are a total of 900,000 single digits in the range from 1 to 1000000.
For any integer greater than 5, where the units digit is 5 then that number can be expressed as the product of n and 5. As such, the number is composite. Therefore all numbers in the range 150 to 200 that have a units digit of 5 are composite,.
To find the number of 5-digit combinations from 1 to 20, we first calculate the total number of options for each digit position. Since the range is from 1 to 20, there are 20 options for the first digit, 20 options for the second digit, and so on. Therefore, the total number of 5-digit combinations is calculated by multiplying these options together: 20 x 20 x 20 x 20 x 20 = 3,200,000 combinations.