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How many times the digit 7 appears between the range 100-475?

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∙ 9y ago

Updated: 4/28/2022

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Amjaad Shanaah ∙

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∙ 3y ago

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Q: How many times the digit 7 appears between the range 100-475?

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How many 80s in 4000?

There are 50 multiples of 80 between 1 and 4000, as 4000 divided by 80 equals 50. However, the question asks for the number of occurrences of the digit "8" in the range from 1 to 4000, not the number of multiples of 80. The digit "8" appears in the units place for numbers 8, 18, 28, ..., 3998, occurring 500 times. Additionally, it appears in the tens place for numbers 80, 81, ..., 89, 180, 181, ..., 189, and so on, occurring 400 times. Therefore, the digit "8" appears 900 times in the range from 1 to 4000.

How many palindromes are there between 900 - 1900?

-1000

If you write 1 to 1000000 how many single digits are there?

There are 9 single digits (1, 2, 3, 4, 5, 6, 7, 8, 9) that are repeated throughout the numbers from 1 to 1000000. Each single digit appears 100,000 times (except for 0, which appears 100,000 times as well). Therefore, there are a total of 900,000 single digits in the range from 1 to 1000000.

What is the digit in the units place of a number is 5 if the no lies between 150 and 200 will be composite or prime?

For any integer greater than 5, where the units digit is 5 then that number can be expressed as the product of n and 5. As such, the number is composite. Therefore all numbers in the range 150 to 200 that have a units digit of 5 are composite,.

How many 5 digit combinations are there from 1-20?

To find the number of 5-digit combinations from 1 to 20, we first calculate the total number of options for each digit position. Since the range is from 1 to 20, there are 20 options for the first digit, 20 options for the second digit, and so on. Therefore, the total number of 5-digit combinations is calculated by multiplying these options together: 20 x 20 x 20 x 20 x 20 = 3,200,000 combinations.

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Related Questions

What is the program to figure out how many numbers from 0 to 9 are needed for 1 to 89 for example?

#include<iostream> #include<array> #include<sstream> std::array<int,10> get_frequency (int range_min, int range_max) { if (range_max<range_min) std::swap (range_min, range_max); std::array<int,10> digit {}; for (int count {range_min}; count<=range_max; ++count) { std::stringstream ss {}; ss << count; std::string s {}; ss >> s; for (auto c : s) { ++digit[c-'0']; } } return digit; } int main () { std::array<int,10> digit {}; digit = get_frequency(1, 89); std::cout << "In the range 1 to 89...\n"; for (int d {0}; d<10; ++d) { std::cout << "\tthe digit " << d << " appears " << digit[d] << " times.\n"; } } Output: In the range 1 to 89... the digit 0 appears 8 times. the digit 1 appears 19 times. the digit 2 appears 19 times. the digit 3 appears 19 times. the digit 4 appears 19 times. the digit 5 appears 19 times. the digit 6 appears 19 times. the digit 7 appears 19 times. the digit 8 appears 19 times. the digit 9 appears 9 times.

How many 11 digit numbers are there?

Eleven digit numbers are those in the range between 9,999,999,999 and 100,000,000,000 exclusive. There are 90,000,000,000 of these.

How many times does 1to50 2?

To clarify your question: If you're asking how many times the number 2 can be counted from 1 to 50, here’s the breakdown: The number 2 appears in the following sequence as a single digit: 2, 12, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 32, 42. In the number 22, the digit 2 appears twice. Let's count the occurrences: In the range 1 to 9, 2 appears once. In the range 10 to 19, 2 appears once (12). In the range 20 to 29, 2 appears 11 times (20, 21, 22 twice, 23, 24, 25, 26, 27, 28, 29). In the range 30 to 39, 2 appears once (32). In the range 40 to 49, 2 appears once (42). In the range 50, 2 does not appear. Summing these, the total number of times the digit 2 appears from 1 to 50 is: 1 (from 1-9) + 1 (from 10-19) + 11 (from 20-29) + 1 (from 30-39) + 1 (from 40-49) = 15 times. So, the digit 2 appears 15 times in the numbers from 1 to 50.

How many four digit numbers are found between 900 and 6000?

The smallest one in that range is 1,000. The largest one in that range is 6,000.All the numbers between 1,000 and 6,000 are 4-digit numbers. There are6,000 - 999 = 5,001of them.

How many 80s in 4000?

There are 50 multiples of 80 between 1 and 4000, as 4000 divided by 80 equals 50. However, the question asks for the number of occurrences of the digit "8" in the range from 1 to 4000, not the number of multiples of 80. The digit "8" appears in the units place for numbers 8, 18, 28, ..., 3998, occurring 500 times. Additionally, it appears in the tens place for numbers 80, 81, ..., 89, 180, 181, ..., 189, and so on, occurring 400 times. Therefore, the digit "8" appears 900 times in the range from 1 to 4000.

What single digit appears most frequently between and including the numbers 1 and 1,000 Hint: look for a pattern?

The single-digit that appears most frequently between and including the numbers 1 and 1000 is the digit "1". To see why this is the case, consider the following pattern: Between 1 and 9, there is one occurrence of the digit "1". Between 10 and 99, there are 10 occurrences of the digit "1" in the tens place (10, 11, 12, ..., 19) and 9 occurrences of the digit "1" in the ones place (21, 31, 41, ..., 91), for a total of 19 occurrences. Between 100 and 999, there are 100 occurrences of the digit "1" in the hundreds place (100, 101, 102, ..., 199), 100 occurrences of the digit "1" in the tens place (110, 111, 112, ..., 119, 121, 131, ..., 191, 201, ..., 291, 301, ..., 391, ..., 901, ..., 991) and 9 occurrences of the digit "1" in the ones place (101, 111, 121, ..., 191), for a total of 210 occurrences. Adding up the number of occurrences for each range, we get: 1 + 19 + 210 = 230 Therefore, the digit "1"

How many 2s between 1 and 300?

To find how many times the digit '2' appears between 1 and 300, we can look at each digit place: hundreds, tens, and units. In the range from 1 to 299, '2' appears 100 times in the tens place (20-29), 30 times in the units place (2, 12, 22, ..., 292), and 100 times in the hundreds place (200-299). Therefore, in total, '2' appears 100 + 30 + 100 = 230 times. However, since we are only considering up to 300 (not including it), the final count remains 230.

How many digit 4 in numbers from 1 to 623?

To determine how many times the digit 4 appears in numbers from 1 to 623, we can consider the units, tens, and hundreds place separately. In the units place, the digit 4 appears once in numbers ending in 4 (4, 14, 24, ..., 614). This happens 62 times. In the tens place, the digit 4 appears 10 times in every hundred numbers (40-49, 140-149, ..., 540-549), so it appears 6 times within the range from 1 to 623. In the hundreds place, the digit 4 appears once in every hundred numbers (400-499), occurring 1 time. Therefore, the digit 4 appears a total of 62 + 6 + 1 = 69 times in numbers from 1 to 623.

What are the differences between normalized and denormalized floating point numbers?

Normalized floating point numbers have a single leading non-zero digit and a fixed exponent range, while denormalized floating point numbers have a leading zero digit and a smaller range of exponents.

How many palindromes are there between 900 - 1900?

-1000

How many 5 digit numbers are odd?

The first 5 digit number is 10,000 and the last is 99,999. Thus there are 90,000 numbers between that range. Half of them are odd & half are even. 45,000 each

What does mean mode and range mean?

Its range, median, and mode.Range is the distance between the two farthest numbers out.Median is the middle number.And mode is the number that appears the most.

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