It depends on the data set, but
if you take the data set 1,2,3
2 is the median and to find the mean you have to add all the numbers and divide by the number of items
so 1+2+3=6 and 6 divided by 3= 2
now the median is 2 and the mean is 2
so this is when they can be the same
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
All sets of 3 consecutive numbers will have the same mean and median
Mean, median, and mode are all equal in a normal distribution.
Yes. In the set (9, 10, 11, 12, 13) 11 is the median and the mean.
Yes.
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
Yes because if the numbers are all the same they can be both mean and median but they do not have to be the same.
No. The mean and median are not necessarily the same. They will be the same if the distribution is symmetric but the converse is not necessarily true. That is to say, a distribution does not have to be symmetric for the mean and median to be the same. For example, the mean and median of {1, 1, 5, 6, 12} are both 5 but the distribution is NOT symmetric.
All sets of 3 consecutive numbers will have the same mean and median
5,6,7
132. You're the the one that stated "normal distribution", thus the same.
(10,10,30,30,30,50,50) (20,20,30,30,30,40,40) These two sets have the same mean, median and mode.
Mean, median, and mode are all equal in a normal distribution.
If it is a symmetric distribution, the median must be 130.
That would provide some evidence that the distribution is symmetric about the mean (or median).
That would provide some evidence that the distribution is symmetric about the mean (or median).
Yes. In the set (9, 10, 11, 12, 13) 11 is the median and the mean.