Well it depends on how many times you roll the cubes. since there's six sides, you multiply them by a number of time you're rolling. For example: 6x3=18. 2out of 18 or 1/9.
1 in 6, or about 0.167
Every number on a number cube is a whole number. (A whole number is a number without a fraction or decimal) So the probability of rolling a whole number on a number cube one time would be 6/6 or 1.
Not Sure
10/3
What is the probability of rolling a 6 the first time and a 1 the second time
0.25 ( P = 0.5 each time)
The probability of the outcomes is 1.
The probability of rolling a 7 at any time on a single die is zero.
Conduct the following experiment: Roll a number cube 50 times. Count the number of times you roll a 2. Divide that number by 50. That is the experimental probability. The answer that I might get may well be different to yours. And if you do you experiment another time, the answer is likely to be different.
2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.
The probability of rolling the same number six times on a standard die is (1 in 6)5 or 1 in 7776, or about 0.0001286. The reason the exponent above is five instead of six is that the probability of rolling "some" number on one die is 1, so you need to look at the probability of the other five dice matching the first die. It would not matter if you rolled one die six times, or six dice one time. The odds are the same.
The experimental probability of anything cannot be answered without doing it, because that is what experimental probability is - the probability that results from conducting an experiment, a posteri. This is different than theoretical probability, which can be computed a priori. For instance, the theoretical probability of rolling a 3 is 1 in 6, or about 0.1667, but the experimental probability changes every time you run the experiment