Well it depends on how many times you roll the cubes. since there's six sides, you multiply them by a number of time you're rolling. For example: 6x3=18. 2out of 18 or 1/9.
1 in 6, or about 0.167
Every number on a number cube is a whole number. (A whole number is a number without a fraction or decimal) So the probability of rolling a whole number on a number cube one time would be 6/6 or 1.
Not Sure
10/3
What is the probability of rolling a 6 the first time and a 1 the second time
0.25 ( P = 0.5 each time)
When rolling a standard six-sided number cube (die) four times, the total number of possible outcomes is (6^4) or 1,296, as each roll has 6 outcomes. The probability of any specific sequence occurring (e.g., rolling a 3 each time) is ( \frac{1}{1296} ). If you're interested in the probability of rolling a specific number at least once over the four rolls, that would require a different calculation involving complementary probabilities.
The probability of the outcomes is 1.
The probability of rolling a 7 at any time on a single die is zero.
2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.
The probability of rolling a 4 on a six-sided die is 1/6. When rolling the die twice, the events are independent, so the probabilities multiply. Therefore, the probability of rolling a 4 both times is (1/6) * (1/6) = 1/36. Thus, the probability of rolling a 4 on both rolls is 1/36.
The probability of rolling the same number six times on a standard die is (1 in 6)5 or 1 in 7776, or about 0.0001286. The reason the exponent above is five instead of six is that the probability of rolling "some" number on one die is 1, so you need to look at the probability of the other five dice matching the first die. It would not matter if you rolled one die six times, or six dice one time. The odds are the same.