When rolling a standard six-sided number cube (die) four times, the total number of possible outcomes is (6^4) or 1,296, as each roll has 6 outcomes. The probability of any specific sequence occurring (e.g., rolling a 3 each time) is ( \frac{1}{1296} ). If you're interested in the probability of rolling a specific number at least once over the four rolls, that would require a different calculation involving complementary probabilities.
The answer depends on how many times it is rolled.
The expectation is 50 times.
It is 0.722... recurring.
Not Sure
10/3
The question does not say which event the probability is required for!
The answer depends on how many times it is rolled.
1/8
The expectation is 50 times.
It is 0.722... recurring.
A number cube is a six sided figure so I'm going to go with 0%
Not Sure
For an ordinary number cube, the answer is 1/6
The experimental probability of a number cube that lands on 5 four times in a twenty toss trial is Pexp(5) = 4/20 = 1/5 = 0.20 = 20%
When a number cube is rolled twice, there are 36 possible outcomes. (1,1),(1,2),....(6,6). (3,3) occurs only once. Therefore, the probability of rolling a 3 both times is 1/36.
10/3
A number cube has six faces, so the probability of any one of them showing on a fair throw is 1 in 6, or about 0.1667.