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The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
The length of a triangle can't be expressed in square units and only its area is expressed in square units
Perimeter of rectangle = 2 x (Length + Width) = 2 x (L + 18) or = (2L + 36) centimetres.
W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42
6x-14
Represent the length of the rectangle by L and the width by W. The perimeter = 2L + 2W = 2(L + W). The area = L x W.
The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
Area=Length X Width
The length of a triangle can't be expressed in square units and only its area is expressed in square units
Perimeter of rectangle = 2 x (Length + Width) = 2 x (L + 18) or = (2L + 36) centimetres.
Volume = 5123
W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42
call width x so length is 3x perimeter is (2*length)+(2*width) so perimeter is 8x
6x-14
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The length of the rectangle is 18cm. The width of the rectangle is 9cm.
A = x times (x + 2) A = x squared + 2x