I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
867 square inches
The area of rectangle is : 60.0
Area of rectangle: 6 times 7 = 42 square inches
To get the area of a rectangle, the formula is length times width, so 13x6= 78 inches.
Surface area of rectangle: 15 times 8 = 120 square inches
867 square inches
Area rectangle: 20 times 40 = 800 square inches
The area of rectangle is : 60.0
The area of rectangle is : 184.0
Area of rectangle: 6 times 7 = 42 square inches
9 inches
Surface area of rectangle: 15 times 8 = 120 square inches
To get the area of a rectangle, the formula is length times width, so 13x6= 78 inches.
it is the area of a solid object times by the square root of the perimiter
3 inches times 5 inches = 15 square inches
To find the area of a rectangle, multiply the length times the width.
To find the area of a rectangle, multiply the length times the width. The result will be in square inches.