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I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.

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Q: When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
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