To find the area of a rectangle, multiply the length times the width.
384
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
It doesn't make any difference what the original dimensions are. If they're both cut in half, the area is reduced to 1/4 of the original area.
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
9" x 4"
16x12=_ and there you go zac 10
192 square inches
9 inches
16 inches 16 inches
384
72 square inches, or 0.5 square foot.
Draw a rectangle, two inches by four inches. Draw intersecting lines at 1 inch intervals so that the entire figure is covered by 1 inch squares. There are 8 of them. The area of the rectangle is 8 square inches, or 2 x 4
Two
Its length is 1+ square root of 66 ft and its width is -1+ square root of 66 ft
Yes, a rectangle can be 17 inches by 1 inch
There is no way to compute the dimension of a rectangle from its area. 40 square inches, you see, could be 1"x40" or 2"x20", or 4"x10", or . . . . . . but they would all be 40 square inches.
You cannot. There is no simple relationship between the area of a polygon and its dimensions. For example a rectangle with an area of 1 sq inch can have any length, L, of 1 or more inches, and a breadth of 1/L inches. There are infinitely many possible values for L and so infinitely many solutions. A question that is in the more general form which simply gives the area of a quadrilateral, rather that a rectangle, there are even more options.