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Q: When the volume of the balloon approaches 0.0 L How do you account for the discrepancy?

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It depends on many things, but if you're going by the equatorial radius as the same size, the balloon should be about 10-15% larger. Note that you can mesure the volume of irregular shapes, thanks to my good friend Archemedes ("Eurika!"). Take a mesuring container large enough to easily hold the balloon and fill it about 2/3 full. Note the volume the water occupies by the water level. Now, immerse the balloon in the water and mesure the volume by the water level again. the difference is the volume of the balloon.

The volume will increase in proportion to the increase in absolute temperature.

The volume of a body and the surface area arerelated but not in a direct way. For a given volume, the smallest surface area of an object is seen then the object is a sphere. As the shape flattens from a sphere, so the surface area becomes larger. When the object approaches an infinitely small thickness, the surface area approaches and infinite size.

18

Volume = 4/3*pi*123 = 7238.229 cubic cm to 3 dp

Related questions

The kinetic energy of the particles inside the balloon increase. This then expands the volume of the balloon.

The volume of the balloon decreases

volume decreases considering the pressure is constant

49.5

I interpret this question to be asking how one might measure the volume of a water balloon without breaking the balloon or emptying it of the water in order to measure its volume. One method is to fill a container with water that will be large enough to contain the water balloon, and then submerging the water balloon in the container. The volume of the balloon will be the apparent volume change of the water in the container. Any measurement will introduce some error. Since water compresses hardly at all, one would expect that submerging the balloon would not significantly change the volume of the balloon. There could be some error if one had to push down on the balloon to make it fully submerge. There will also be some measurement error in determining the volume change.

Because the gas inside expands with the heat

The volume become 197 mL. (Avogadro law)

the volume of air inside the balloon increases while the pressure of balloon decreases thus balloon inflates

For a balloon that is sealed and not full the volume of air inside the balloon will increase as it is heated. This is not however how hot air balloons work. A hot air balloon is essentially a fixed volume when it is inflated. If the air inside the balloon is heated the air inside becomes less dense so some of the air exits the balloon via the mouth of the balloon. As the air inside the balloon cools it becomes more dense so some air is ingested via the mouth of the balloon to keep it full. With each heating and cooling cycle, the pressure inside the balloon remains constant, the volume of the balloon remains constant but there is this movement of air out of and back into the balloon. P=VT Poop

If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).

If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).

A balloon has some mass and volume. Therefore it will rise in the atmosphere until that mass/volume is equal to that of the local atmosphere.