Wiki User
∙ 10y agoThe volume will increase in proportion to the increase in absolute temperature.
Wiki User
∙ 10y agoA child takes a helium balloon on a plane from Denver (with an air pressure of 0.83 atm) on a cool day when the temperature is 20C to Boston (at sea level, with an air pressure of 1.0 atm) where the temperature is 5C. Assume that no gas escapes from the balloon during the flight. What is the volume of the balloon in Boston, relative to its size in Denver
Avogadro's Law: Doubling the number of moles of gas doubles its volume, if temperature and pressure aren't changed.A flat tire takes up less space than an inflated tire.Lungs expand as they fill with air. Exhaling decreases the volume of the lungs.A balloon filled with helium weighs much less than an identical balloon filled with air. (Avogadro's Law implies that equal volumes contain equal numbers of molecules, when pressure and temperature are held constant. Since both balloons contain the same number of molecules, and since helium atoms have lower mass than either oxygen molecules or nitrogen molecules in air, the helium balloon is lighter.)Wet air is less dense than moist air (see the FAQ on gases for an explanation).Or simply, all in all, it's just a matter of quantity of gas. (Quantity refers to it's moles). And as the quantity increases, the volume of it's containre, increases to. :)
Effusion
The water has a mass of roughly 560 grams, depending on its purity and temperature. We have no idea what the mass of the balloon is.
The ratio of temperatures must be calculated for the absolute temperatures - not temps measures on the Celsius scale. So, the temperature increases from 273.15 K to 333.15 K. 333.15/273.15 = 1.2197 Therefore, the volume will increase by a multiple of 1.2197. This answer assumes that all other factors remain unchanged. That is unlikely since the elasticity of the balloon is likely to be affected by the change in temperature.
When a balloon is squeezed to half its volume at constant temperature, the air pressure inside the balloon increases. This is because the number of air molecules remains constant while the volume decreases, leading to the molecules being packed closer together and increasing the pressure.
The volume of the weather balloon would increase. This is because as the temperature of a gas increases, the molecules move faster and spread out more, leading to an increase in volume according to Charles's Law.
== == According to Charles's Law, "At constant pressure, the volume of a given mass of an ideal gas increases or decreases by the same factor as its temperature (in Kelvin) increases or decreases." Therefore, if the temperature of the gas is decreased, the volume of the gas will decrease proportionally, and the balloon will contract.
When the temperature of a gas in a balloon increases, the volume of the balloon will also increase due to the gas molecules moving faster and exerting more pressure on the walls of the balloon, causing it to expand.
No, it is not possible for the balloon to naturally expand four times its initial volume while the temperature remains constant. According to Boyle's Law, at constant temperature, the pressure and volume of a gas are inversely proportional. Since the atmospheric pressure remains constant, the balloon's pressure of 200.0kPa would need to increase to expand, which cannot happen at constant temperature.
As a balloon rises, the pressure inside the balloon decreases. This is because the atmospheric pressure outside the balloon decreases with altitude, causing the balloon to expand as the pressure inside remains relatively constant.
Isothermal is where pressure and/or volume changes, but temperature remains constant. Pressure, Volume, and Temperature are related as: PV = nRT =NkT for an ideal gas. Here, we see that since a balloon's volume is allowed to change, its pressure remains relatively constant. Whenever there is a pressure change, it'll be offset by an equivalent change in volume, thus temperature is constant.
The pressure inside the balloon will increase due to the increase in temperature caused by the rubbing (which is a form of mechanical work). According to the ideal gas law, pressure is directly proportional to temperature when volume is constant.
Assuming pressure remains constant, we can use Charles's Law which states that the volume of a gas is directly proportional to its temperature. V1/T1 = V2/T2. Substituting the given values, we find that the new volume of the balloon at 350 K will be 3.5 liters.
If the pressure is kept constant while increasing the temperature of the air in a balloon, the volume of the gas inside the balloon would change. This is because as the temperature rises, the gas molecules gain energy and move faster, leading to an increase in volume to maintain a constant pressure.
As air on the surface of the Earth warms, its density decreases. This is because warmer air molecules have higher kinetic energy, causing them to spread out and occupy a larger volume, resulting in lower density. Conversely, when air cools, its density increases as the molecules contract and come closer together.
When you squeeze a party balloon to 0.8 volume, the pressure in the balloon will be 1.25 times greater. This is because the pressure in a confined gas is directly proportional to the volume of the container when the temperature remains constant, as described by Boyle's Law.