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The volume will increase in proportion to the increase in absolute temperature.

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A child takes a helium balloon on a plane from Denver (with an air pressure of 0.83 atm) on a cool day when the temperature is 20C to Boston (at sea level, with an air pressure of 1.0 atm) where the temperature is 5C. Assume that no gas escapes from the balloon during the flight. What is the volume of the balloon in Boston, relative to its size in Denver


Why does a balloon in a constant environment get smaller and smaller?

Effusion


Examples of Avogadro's law in everyday life?

Avogadro's Law: Doubling the number of moles of gas doubles its volume, if temperature and pressure aren't changed.A flat tire takes up less space than an inflated tire.Lungs expand as they fill with air. Exhaling decreases the volume of the lungs.A balloon filled with helium weighs much less than an identical balloon filled with air. (Avogadro's Law implies that equal volumes contain equal numbers of molecules, when pressure and temperature are held constant. Since both balloons contain the same number of molecules, and since helium atoms have lower mass than either oxygen molecules or nitrogen molecules in air, the helium balloon is lighter.)Wet air is less dense than moist air (see the FAQ on gases for an explanation).Or simply, all in all, it's just a matter of quantity of gas. (Quantity refers to it's moles). And as the quantity increases, the volume of it's containre, increases to. :)


You filled a balloon with 560 ml of water the balloon and water have a mass of?

The water has a mass of roughly 560 grams, depending on its purity and temperature. We have no idea what the mass of the balloon is.


What change in volume of the balloon is observed between 0 degrees C and 60 degrees C?

The ratio of temperatures must be calculated for the absolute temperatures - not temps measures on the Celsius scale. So, the temperature increases from 273.15 K to 333.15 K. 333.15/273.15 = 1.2197 Therefore, the volume will increase by a multiple of 1.2197. This answer assumes that all other factors remain unchanged. That is unlikely since the elasticity of the balloon is likely to be affected by the change in temperature.

Related Questions

What happens to the air pressure inside a balloon when it is squeezed to half its volume at constant temperature?

When a balloon is squeezed to half its volume at constant temperature, the air pressure inside the balloon increases. This is because the number of air molecules remains constant while the volume decreases, leading to the molecules being packed closer together and increasing the pressure.


What will happen to the balloon when the temperature increases will the balloon burst?

When the temperature increases, the air inside the balloon will expand, causing the balloon to inflate. If the temperature increase is too drastic, the pressure inside the balloon can exceed its limits and cause it to burst. However, this depends on the material and durability of the balloon.


What woul happen to the volume of the 100L weather balloon if its temperature increases from 25 C TO 125 C while the external pressure remain constant?

The volume of the weather balloon would increase. This is because as the temperature of a gas increases, the molecules move faster and spread out more, leading to an increase in volume according to Charles's Law.


Why would cooling the gas in an air balloon make the balloon contract?

== == According to Charles's Law, "At constant pressure, the volume of a given mass of an ideal gas increases or decreases by the same factor as its temperature (in Kelvin) increases or decreases." Therefore, if the temperature of the gas is decreased, the volume of the gas will decrease proportionally, and the balloon will contract.


If a balloon is heated what happens to the pressure of an air inside the balloon if the volume remains constant?

If a balloon is heated, the temperature inside the balloon increases, causing the air molecules to move faster and collide more frequently with the walls of the balloon. This increase in collisions leads to an increase in pressure inside the balloon, assuming the volume remains constant according to the ideal gas law (P1/T1 = P2/T2).


Is it possible for a balloon with an initial pressure of 200.0kPa to naturally expand four times its initial volume when the temperature remains constant and atmospheric pressure is 101.3kPa?

No, it is not possible for the balloon to naturally expand four times its initial volume while the temperature remains constant. According to Boyle's Law, at constant temperature, the pressure and volume of a gas are inversely proportional. Since the atmospheric pressure remains constant, the balloon's pressure of 200.0kPa would need to increase to expand, which cannot happen at constant temperature.


As a balloon rises does the presure inside the bag of balloon increases or decreases?

As a balloon rises, the pressure inside the balloon decreases. This is because the atmospheric pressure outside the balloon decreases with altitude, causing the balloon to expand as the pressure inside remains relatively constant.


How is isothermal possible in a balloon?

Isothermal is where pressure and/or volume changes, but temperature remains constant. Pressure, Volume, and Temperature are related as: PV = nRT =NkT for an ideal gas. Here, we see that since a balloon's volume is allowed to change, its pressure remains relatively constant. Whenever there is a pressure change, it'll be offset by an equivalent change in volume, thus temperature is constant.


If a balloon is rubbed vigorously what happens to the pressure of the air inside the balloon if the volume remains constant?

The pressure inside the balloon will increase due to the increase in temperature caused by the rubbing (which is a form of mechanical work). According to the ideal gas law, pressure is directly proportional to temperature when volume is constant.


What gas law describes when adding gas to a balloon will cause the volume to decrease?

Boyle's Law describes the relationship between the pressure and volume of a gas at constant temperature. According to Boyle's Law, when adding gas to a balloon, the volume will decrease if the pressure inside the balloon increases.


What happens to the pressure of the air inside the balloon if the volume remains constant if the balloon is heated?

Pressure increases.Take a look at the relationship:PV=nRTR is a constant. n is the amount of gas, which would be held constant in a sealed balloon. So:P1 V1 / T1 = P2 V2 / T21- before2- afterThis algebraic equation can help predict the outcome of other cases as well.taking just the balloon first, it is a solid body(flexible), on heating it undergoes cubical expansion, so the first thng that happens is the container(balloon) expands so untill a particular expansion of it the volume of air inside increases(gases dont have a fixed volume) they occupy the area they have .


Suppose the temperature of the air in a balloon is increased if the pressure remains constant.. what quantity must change Would it be Volume or Number of molecules or Compressibility OR Adhesion?

If the pressure is kept constant while increasing the temperature of the air in a balloon, the volume of the gas inside the balloon would change. This is because as the temperature rises, the gas molecules gain energy and move faster, leading to an increase in volume to maintain a constant pressure.