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∙ 11y agoVolume = 4/3*pi*123 = 7238.229 cubic cm to 3 dp
Wiki User
∙ 11y agoDiameter is a length measurement. Cubic inches is a volume measurement. Diameter cannot be measured in or converted to cubic inches.
Volume = 4/3*pi*25.53 = 69455.90118 or about 69456 cubic cm Liters = 69456/1000 = 69.456
Diameter and area of a circle. 2 times the diameter ==> 4 times the original area.Length and area of a rectangle. 2 times the length ==> 4 times the original area.Diameter and volume of a spherical balloon. 2 times the diameter ==> 8 times the original volume.
Volume = Height * Area of Circle Area of Circle = pi*(Diameter/2)^2 Height = Diameter Volume = Diameter*(pi*(Diameter/2)^2) Volume = (pi/4)*Diameter^3 Diameter = (4/pi) * Volume ^ (1/3) Diameter = (4/3.14)*220^(1/3) ≈ 6.54 cm
The volume of a sphere with a diameter of 8cm is about 268cm3
As a balloon rises in the air, the volume or size of the balloon increases. This is because the atmospheric pressure decreases as the balloon gains altitude, causing the air inside the balloon to expand and the balloon to inflate.
The mass of the balloon is independent. Atmospheric pressure will not change this because atoms are not being added or taken away from the balloon itself or its contents. The volume of the balloon will change, however, as it will expand or compress in response to the atmospheric pressure around it. The volume, therefore, is a dependent variable in this situation.
As the weather balloon rises through the stratosphere, the atmospheric pressure decreases. This lower pressure causes the gas inside the balloon to expand, leading to an increase in volume. The gas molecules have more space to spread out due to the reduced external pressure.
Diameter is a length measurement. Cubic inches is a volume measurement. Diameter cannot be measured in or converted to cubic inches.
The change in solution volume will be the volume of the sphere. Let's call that V We know that the volume of a sphere is 4/3 Pi x r^3 So the cube root of 3v/4Pi is the radius, double it and you have the diameter. OR Volume of sphere is 1/6 Pixd^3 so 6V/Pi is the diameter cubed. Take the cube root of 6V/Pi and that is the diameter.
Use the formula for a sphere. First divide the diameter by 2; that will give you the radius.
Volume = 4/3*pi*25.53 = 69455.90118 or about 69456 cubic cm Liters = 69456/1000 = 69.456
No, it is not possible for the balloon to naturally expand four times its initial volume while the temperature remains constant. According to Boyle's Law, at constant temperature, the pressure and volume of a gas are inversely proportional. Since the atmospheric pressure remains constant, the balloon's pressure of 200.0kPa would need to increase to expand, which cannot happen at constant temperature.
It would take approximately 0.85 cubic meters of helium to fill a 3 ft balloon.
The kinetic energy of the particles inside the balloon increase. This then expands the volume of the balloon.
Helium is less dense than air, so a balloon filled with helium is lighter than the same volume of air. This buoyancy force allows the helium-filled balloon to rise. On the other hand, a balloon filled with air has the same density as the surrounding air, so there is no buoyant force to make it rise.
First, you must decide whether with "size" you mean the diameter (or equivalently the radius), or the volume. Assuming you mean the volume, an ideal gas will shrink to half the volume if the temperature is reduced to one-half, so that might be a good approximation. However, the temperatures must first be converted to Kelvin. (If you mean the diameter, for the diameter to get reduced to 1/2 the original diameter, the volume would get reduced by 1/8 of the original volume).