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When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what will be it maximum height?
Wiki User
∙ 11y ago
'Maximum height' means the exact point at which the velocity changes from
upward to downward. At that exact point, the magnitude of the velocity is zero.
It doesn't matter what the velocity was when it left your hand. That number
determines the maximum height, but the velocity at that height is always zero.
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Thus using the formula: (vf)e2 = (vi)e2+2*a*d
vf = final velocity = 0 m/s
vi = initial velocity = 10 m/s
a = acceleration = gravity = - 9.81 m/s/s
d = displacement (distance) = ?
e is designating that the next figure is an exponent in the formula
So the formula is:
(0)e2 = (10)e2 + (2 * -9.81 * d)
0 = 100 + -19.62d
adding 19.62d to both sides of the equation
19.62d = 100
dividing by 19.62
d = ~ 5.097 meters
Wiki User
∙ 11y ago
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