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When rolling a pair of dice there are 6∙6 = 36 possible outcomes.

The outcomes that give a sum of 5 are 4, [(1,4), (2,3), (3,2), (4,1)].

So the probability of not rolling a sum of 5 is:

P(NOT 5) = 1 - P(5) = 1 - 4/36 = 32/36 = 8/9 = 0.8888... ≈ 88.9%

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Q: When two dice are rolled find the probability of not rolling a sum of 5?
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