With 2 six-sided dice, there are 36 outcomes. The answer will depend on the meaning of between. First, here's a table of the number of possibilities to obtain each sum:
So if between means 6 through 10, then add up all of the above and you have 13 outcomes which are not between 5 & 11. So there are (36-13=23) outcomes which are between.
So the probability is 23/36. If you meant to include so that it was 5 through 11, then add 6 outcomes, so it is 29/36.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 1, if the dice are rolled often enough.
The probability is 8/36 or 2/9
1/12 or .083
If they are normal dice, the probability is 0.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 1, if the dice are rolled often enough.
The probability is 8/36 or 2/9
It is 1/6.
1/12 or .083
1/12
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
Zero. The minimum value of two dice being rolled is two.
35 in 36, or about 0.9722
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.