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Two numbers such that their sum is 8 and their difference is also 8?
This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
How do you solve x plus y equals 10 and y equals x plus 8?
If x + y = 10 and y = x + 8Substitute y = x + 8 into x + y = 10Which gives; x + x + 8 = 10So; 2x + 8 = 10( - 8 from both sides); 2x=2So: x =1. Substitute back into y = x + 8And therefore y = 1 + 8 ; y=9
-x+ 4 y>-8 x+y8 y?
-x+ 4y>-8, x+y≤3 y≤3-x -x+4(3-x)>-8 -x+12-4x>-8 12-5x>-8 -5x>-20 x>4 y≤3-(4) y≤-1
What is the answer to x- y equals y if x equals 8?
For this problem, write it out... x-y=y... x=2y...8=2y...8/2=y...4=y First, I made both y's on the same side( I added a y to both sides). Then, I replaced the x with an 8. Then, I divide out the 2 from both sides. This leaves me with 4=y So... x=8, y=4, 8-4=4
What is 8 times a number x decreased by y?
It is difficult to tell what expression you are trying to convey. 8 multiplied by x, and then take y away, is 8x-y x take away y, and then 8 multiplied by this number, is 8(x-y) 8 multiplied by x, and divided by y is 8x/y
How do you factor this x raised to the power of 8 y raised to the power of 8?
x^8 - y^8 = (x - y)(x + y)(x^2 + y^2)(x^4 + y^4)
X plus y equals 10 y equals X plus 8?
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
What is the solution of y x 4 y 3x 8?
If you mean: y = x+4 and y = 3x+8 then x = -2 and y = 2
X plus y equals 10 y equals X plus 8 subsitute this method?
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
Two numbers such that their sum is 8 and their difference is also 8?
This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
How do you solve x plus y equals 10 and y equals x plus 8?
If x + y = 10 and y = x + 8Substitute y = x + 8 into x + y = 10Which gives; x + x + 8 = 10So; 2x + 8 = 10( - 8 from both sides); 2x=2So: x =1. Substitute back into y = x + 8And therefore y = 1 + 8 ; y=9
Is x plus y equals 8 a inverse varition?
x+y=8 y=-x+8 is not an inverse variation. However, y=8/x is an inverse variation or y varies inversely as x.
-x+ 4 y>-8 x+y8 y?
-x+ 4y>-8, x+y≤3 y≤3-x -x+4(3-x)>-8 -x+12-4x>-8 12-5x>-8 -5x>-20 x>4 y≤3-(4) y≤-1
What is y equals x plus 8?
y=x+8 is a linear equation. Y is the Y point on a graph, X is the slope, and 8 is the y intercept
If 4 multiplied by y eqeals x and x added by y eqeals 10 what is the value of x and y?
14
What are two numbers whose sum is 52 and difference is 8?
Let this numbers be x and y, then x + y = 52 x - y = 8 x = 8 + y x + y = 52 substitute 8 + y for x into the first equation; 8 + y + y = 52 8 + 2y = 52 subtract 8 to both sides; 2y = 44 divide by 2 to both sides; y = 22 x = 8 + y substitute 22 for y into the equation; x = 8 + 22 x = 30 Thus this numbers are 22 and 30. 22 & 30
What is a solution to these equations X plus Y equals -8 and 2x - y equals 4?
x+y=-8 2x-y=4 y=-x-8 2x+x+8=4 3x=-4 x=-4/3 -4/3 + y= -8 y = -8 + 4/3 y= -6 2/3
