If you mean: x+y = 8 and -x+2y = 7 then they are simultaneous equations whose solutions are x = 3 and y = 5
If you mean: x+y = 8 and -x+2y = 7, then they are simultaneous equations whose solutions are x = 3 and y = 5.
x + y = 4 or y = -x + 4 To get X-intercept, make y = 0, then 0 = -x + 4, or x = 4To get Y-intercept, make x = 0, then y = -0 + 4, or y = 4
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If this is an equation you left out the equal sign. Do you mean y8=y12-4. If so add 4 to both sides. You have 4+y8=y12. Then substract y8 from both sides. You have 4=y4. Divide both sides by 4. You have y=1.
If you mean: x+y = 8 and -x+2y = 7 then they are simultaneous equations whose solutions are x = 3 and y = 5
If you mean: x+y = 8 and -x+2y = 7, then they are simultaneous equations whose solutions are x = 3 and y = 5.
given: x - 4 = -y or, -y = x - 4 or, y = -(x - 4) or y = -x + 4 or y = 4 - x i.e. for x > 4, the equation x - 4 = -y is true.
-12 x8 y8 / 3x4 y2 = -4 x4y6 First: divide -12 by 3 which equals -4 Second: divide x to the power of 8 by x to the power of 4 by subtracting the two powers ( 8-4 ) which will equal x to the power of 4 Third: divide y to the power of 8 by y to the power of 2 by subtracting the two powers ( 8-2 ) which will equal y to the power of 6
y=-x+4
x + y = 4 or y = -x + 4 To get X-intercept, make y = 0, then 0 = -x + 4, or x = 4To get Y-intercept, make x = 0, then y = -0 + 4, or y = 4
x^(4)*y*x^(5)*yMultiply x^(4) by y to get x^(4)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(4)y*x^(5)*yMultiply x^(4)y by x^(5) to get x^(9)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y*yMultiply x^(9)y by y to get x^(9)y^(2).(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y^(2)To find the derivative of x^(9)y^(2), multiply the base (x) by the exponent (9), then subtract 1 from the exponent.(d)/(dx) x^(4)*y*x^(5)*y=9x^(8)y^(2)The derivative of x^(4)*y*x^(5)*y is 9x^(8)y^(2).9x^(8)y^(2)
x-y=4 x=y+4
x=9; y=4; x=x+y; #x=13;y=4; y=x-y; #y=13-4=9; x=x-y; #x=13-9=4;
The GCF of y3, y7, y8 is y3