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Pr(At least one head in 3 tosses) = 1 - Pr(No heads in 3 tosses)

= 1 - Pr(3 tails in three tosses) = 1 - [Pr(T)*Pr(T)*Pr(T)] since the three tosses are independent.

= 1 - 1/2 * 1/2 *1/2 = 1 - 1/8 = 7/8

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Q: When you Toss a coin 3 times and what is the probability of getting at least one head?
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Related questions

If you toss a coin 1000 times what is the probability of getting tales?

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What is the probability of getting a head if coin is tossed 5 times?

The probability of getting a head on each occasion if a coin is tossed five times is equal to 1/2 x 1/2 x 1/2 x 1/2 x 1/2 (that is, 1/25) = 1/32 or one in thirty-two. The probability of getting a head on the fifth toss is 1/2. All other tosses are independent of the fifth toss. The probability of getting at least one head when tossing the coin 5 times: Since there are 32 possible combinations and only one of those combinations is all tails you could expect to toss a combination with a head 31/32 times. The probability is 0.96875.