Pr(At least one head in 3 tosses) = 1 - Pr(No heads in 3 tosses)
= 1 - Pr(3 tails in three tosses) = 1 - [Pr(T)*Pr(T)*Pr(T)] since the three tosses are independent.
= 1 - 1/2 * 1/2 *1/2 = 1 - 1/8 = 7/8
1 out of 16
If you toss them enough times, the probability is 1. For just one toss the probability is 1/4.
7/10
Since each event is independent, the probability remains at 0.5.
It is 60/100 = 0.6
50% or 5
1 in 2
1 out of 16
The probability is still 50%
If you toss them enough times, the probability is 1. For just one toss the probability is 1/4.
7/10
10 out of 32
Since each event is independent, the probability remains at 0.5.
The probability of getting a head is 1/2 and if you toss it 4 times, the probability of 4 heads is (1/2)^4=1/16 since the tosses are independent events.
It is 60/100 = 0.6
the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.
The probability of getting a head on each occasion if a coin is tossed five times is equal to 1/2 x 1/2 x 1/2 x 1/2 x 1/2 (that is, 1/25) = 1/32 or one in thirty-two. The probability of getting a head on the fifth toss is 1/2. All other tosses are independent of the fifth toss. The probability of getting at least one head when tossing the coin 5 times: Since there are 32 possible combinations and only one of those combinations is all tails you could expect to toss a combination with a head 31/32 times. The probability is 0.96875.