16 and 240
It is easier to multiply
It's easier to multiply
To find the partial products of 62 x 45, we can break it down into simpler components. First, we multiply 60 (from 62) by 40 (from 45) to get 2400. Then, we multiply 60 by 5 to get 300, and finally, we multiply 2 (from 62) by 40 to get 80, and 2 by 5 to get 10. Adding these partial products together: 2400 + 300 + 80 + 10 gives us a total of 2790.
To find the partial products of 28 and 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the tens place of 43), which gives you 84 (28 × 3). Then, multiply 28 by 40 (the tens place of 43 multiplied by 10), resulting in 1120 (28 × 40). The partial products are 84 and 1120.
511 and 2100
how to find the partial products of a number
To find the partial products for the multiplication of 357 and 48, you can break down the numbers. For instance, you can express 48 as 40 + 8. Then, multiply 357 by each part: (357 \times 40 = 14,280) and (357 \times 8 = 2,856). The partial products are 14,280 and 2,856.
To find the partial products of 452 times 12, you can break it down by multiplying each digit of 12 by the entire number 452. First, multiply 452 by 2 (the ones place), which gives you 904. Then, multiply 452 by 10 (the tens place), resulting in 4520. The partial products are 904 and 4520, which can be added together to get the final product of 5424.
To find the partial products of 35 x 7, you can break down 35 into its place values, which are 30 and 5. Then, multiply each part by 7: 30 x 7 = 210 5 x 7 = 35 Finally, add the partial products together: 210 + 35 = 245. Thus, 35 x 7 = 245.
To find the partial product of 56 and 31, we can break down the multiplication into simpler parts. First, we can multiply 56 by 30 (which is 31 rounded down) to get 1680. Then, we multiply 56 by 1 (the remainder when 31 is broken down) to get 56. The partial products are 1680 and 56.
To find the partial products for 38 times 55, you can break it down into simpler components. First, split 55 into 50 and 5. Then, multiply 38 by each of these components: ( 38 \times 50 = 1900 ) ( 38 \times 5 = 190 ) The partial products are 1900 and 190. To find the total, you would then add these two products together: ( 1900 + 190 = 2090 ).
To find the partial products for 28 times 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the ones place of 43), which equals 84. Next, multiply 28 by 40 (the tens place of 43), which equals 1120. Finally, add the two partial products together: 84 + 1120 = 1204. Thus, 28 times 43 equals 1204.