To find the partial products of 28 and 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the tens place of 43), which gives you 84 (28 × 3). Then, multiply 28 by 40 (the tens place of 43 multiplied by 10), resulting in 1120 (28 × 40). The partial products are 84 and 1120.
6
43% of 28= 43% * 28= 0.43 * 28= 12.04
They are: 30*20, 30*8, 2*20 and 2*8.
To show partial products for the multiplication problem 52 x 43, first break down each number into its place values: 52 can be expressed as 50 + 2 and 43 as 40 + 3. Next, multiply each part: 50 x 40 = 2000, 50 x 3 = 150, 2 x 40 = 80, and 2 x 3 = 6. Finally, add the partial products together: 2000 + 150 + 80 + 6 = 2236, so 52 x 43 equals 2236.
To find the partial product of 4 x 27, you can break down 27 into its components. For example, 27 can be expressed as 20 + 7. Then, you calculate the partial products: 4 x 20 = 80 and 4 x 7 = 28. Adding these together gives you a total of 80 + 28 = 108, so the partial products lead to the final result of 4 x 27 = 108.
6
20 x 40 = 800 8 x 40 = 320 3 x 20 = 60 3 x 8 = 24
They are 600, 240, 80 and 32.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
43% of 28= 43% * 28= 0.43 * 28= 12.04
They are: 30*20, 30*8, 2*20 and 2*8.
how to find the partial products of a number
71
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
60 x 40 = 2400 8 x 40 = 320 60 x 3 = 180 8 x 3 = 24 68 x 43 = 2924
5630 is a single number and single numbers do not have partial products.
the partial products for 12 and 3 30 and 6 :)