To find the partial products of 28 and 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the tens place of 43), which gives you 84 (28 × 3). Then, multiply 28 by 40 (the tens place of 43 multiplied by 10), resulting in 1120 (28 × 40). The partial products are 84 and 1120.
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To find the partial products for 128 x 43, we can break down the multiplication using the distributive property. We can express 43 as 40 + 3. Therefore, the partial products are calculated as follows: 128 x 40 = 5120 and 128 x 3 = 384. Adding these together gives the total: 5120 + 384 = 5504.
To find the partial products of 48 times 28, we can break down the numbers. We can express 48 as 40 + 8 and 28 as 20 + 8. Then, we calculate the partial products: 40 × 20 = 800 40 × 8 = 320 8 × 20 = 160 8 × 8 = 64 Adding these together gives 800 + 320 + 160 + 64 = 1344. Thus, the product of 48 and 28 is 1344.
43% of 28= 43% * 28= 0.43 * 28= 12.04
They are: 30*20, 30*8, 2*20 and 2*8.
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To find the partial products for 128 x 43, we can break down the multiplication using the distributive property. We can express 43 as 40 + 3. Therefore, the partial products are calculated as follows: 128 x 40 = 5120 and 128 x 3 = 384. Adding these together gives the total: 5120 + 384 = 5504.
20 x 40 = 800 8 x 40 = 320 3 x 20 = 60 3 x 8 = 24
They are 600, 240, 80 and 32.
To find the partial products of 48 times 28, we can break down the numbers. We can express 48 as 40 + 8 and 28 as 20 + 8. Then, we calculate the partial products: 40 × 20 = 800 40 × 8 = 320 8 × 20 = 160 8 × 8 = 64 Adding these together gives 800 + 320 + 160 + 64 = 1344. Thus, the product of 48 and 28 is 1344.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
To find the partial products of 42 and 28, you can break down each number into its place values. For 42, you have 40 and 2, and for 28, you have 20 and 8. The partial products are calculated as follows: (40 \times 20 = 800), (40 \times 8 = 320), (2 \times 20 = 40), and (2 \times 8 = 16). Adding these together, (800 + 320 + 40 + 16 = 1176).
43% of 28= 43% * 28= 0.43 * 28= 12.04
They are: 30*20, 30*8, 2*20 and 2*8.
To show partial products for the multiplication problem 52 x 43, first break down each number into its place values: 52 can be expressed as 50 + 2 and 43 as 40 + 3. Next, multiply each part: 50 x 40 = 2000, 50 x 3 = 150, 2 x 40 = 80, and 2 x 3 = 6. Finally, add the partial products together: 2000 + 150 + 80 + 6 = 2236, so 52 x 43 equals 2236.
To find the partial product of 4 x 27, you can break down 27 into its components. For example, 27 can be expressed as 20 + 7. Then, you calculate the partial products: 4 x 20 = 80 and 4 x 7 = 28. Adding these together gives you a total of 80 + 28 = 108, so the partial products lead to the final result of 4 x 27 = 108.
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