4 and 25 are.
They are: 25 minus 4 = 21
25 and 4 or 121 and 100
They are: 25-4 = 21
112 - 102 = 21
16
44
I think the question may refer to which two squares differ by 21. Two solutions : 112 - 102 = 121 - 100 = 21. 52 - 22 = 25 - 4 = 21.
25
The spacing between any two consecutive square numbers (n) and (n+1) is equal to (2n +1), so for 2n+1 =21, n =10 and the numbers are 121 and 100.However, there is a non-consecutive pair as well: 25 and 4.The squares lower than 100 are 1, 4, 9, 16, 25, 36, 49, 64, and 81, and an examination of these shows that there are no other pairs that satisfy the conditions.
223 and 21 if you multiply them. 9366 and 2 if you divide them. 4600 and 83 if you add them. 4686 and 3 if you subtract them.
There are an infinite amount of answers to that, like: 25 - 0 30 - 5 21 - -4 118 - 93
20 and 1 Seems to be a common problem. Add the sum to the difference and divide by 2 gives one number. Then start over and subtract the smaller of the two givens from the larger and then divide by 2 to get the other number. So here you have (21+19)/2 and (21-19)/2