If: C = 2r Then: r = C/2
b = sqrt32 or 4 root 2
pythagoras
no
c=1225.
If: C = 2r Then: r = C/2
4
C equals the square root of 1000 or 31.622776601683793319988935444327...
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
2r(pi)=C where C is circumference. Therefore the radius equals C/2(pi)
b = sqrt32 or 4 root 2
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
pythagoras
Because the value of C equals 13
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
Pascal
you use A squared plus B squared equals C squared