56
If a = b then it is a circle; otherwise it is an ellipse.
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
Equation of circle: x^2 +y^2 -10x +6y -15 = 0 Completing the squares: (x-5)^2 +(y+3)^2 = 49 square units Therefore center of circle is at (5, -3) and its radius is 7 units
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
A linear equation.
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
(-4,3)
(-7,5)
At the center, (x, y) = (-2, 5)
That's the equation of a circle with its center at the origin and a radius of 8.
It is the equation of a circle with radius of 6 and its center at the origin.
(-4,-6)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
(-5, 3)
(-4, 3)
(8,-8)