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What number has a remainder of 1 when divided by 6 and a remainder of 2 when divided by 5?
7, 37, 67, 97, 127, and an infinite number of other numbers in this series (starting with 7 and increasing in increments of 30) have a remainder of 1 when divided by 6 and a remainder of 2 when divided by 5.
How many different natural numbers will each leave a remainder of 5 when divided into 47?
Well, isn't that a happy little math problem! When a number is divided by another number, we get a quotient and a remainder. In this case, we are looking for natural numbers that leave a remainder of 5 when divided into 47. So, we start by listing some numbers that fit this description: 5, 10, 15, 20, 25, 30, 35, 40, and 45. That's 9 different numbers in total that will leave a remainder of 5 when divided into 47.
What number divided by 5 leaves a remainder of 4?
The first five numbers which when divided by 5 leave a remainder of 4 are: 4 = 4/5 = 0 remainder 4 9 = 9/5 = 1 remainder 4 14 = 14/5 = 2 remainder 4 19 = 19/5 = 3 remainder 4 24 = 24/5 = 4 remainder 4 The pattern continues in this way.
What number leaves a remainder of 4 when divided by 5 a remainder of 5 when divided by 6 and a remainder of 6 when divided by 7?
209
What is the remainder when 27 is divided by 5?
5.4
What is the remainder when 29 is divided by 5?
5.8
What is the remainder of 28 divided by 5?
5.6
What is the remainder when 35 is divided by 6?
5.8333
What is the remainder when 37 divided by 5?
7.4
What is 360 divided by 5 with the remainder?
72
What is the remainder when 27 is divided by five?
27 divided by 5 is 5 with remainder 2
What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 5?
It is 98910.
