After a second, the ball will still have a horizontal velocity of 8 meters per second. It will also have a vertical velocity of 9.8 meters per second (Earth's acceleration is about 9.8 meters per square second). The combined speed (using the Law of Pythagoras) is about 12.65 meters per second.
The ball's speed is 9.4 meters per second.
Momentum = (mass) x (speed) (1 x 2) = (2 x 1). Their momenta are equal.
The speed of a ball thrown horizontally remains constant, so it will still be 9 meters per second one second later. Since there is no vertical acceleration, only the horizontal motion occurs.
48 metres per second.
Average speed is calculated by dividing the total distance traveled by the total time taken. In this case, 32 meters divided by 0.8 seconds is 40 m/s. Therefore, the average speed of the bowling ball is 40 m/s.
In a vacuum, like the moon, the acceleration due to gravity is about 9.8 meters per second squared, so each second the speed of the ball increases by 9.8 meters per second. On Earth, with air resistance, the acceleration due to gravity is about 9.81 meters per second squared.
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
speed = distance/time --> time = distance/speed = (30 m)/(50 m/s) = 0.6 seconds
Ignoring Air Resistance, on earth near the earths surface gravity applies a force on all bodies. The acceleration the ball will experience is -9.8 meters per second per second (i.e. it will slow the ball down. When the ball then falls to the ground from the apogee of the throw it will continue to accelerate at 9.8 meters per second per second per second and will hit the ground at the same speed it left the ground originally. So each second it will slow by 9.8 meters per second. 9.8 meters per second, (or 32.2 feet per second), if the experiment is carried out on or near the surface of the earth. 1.6 meters (5.25 feet) per second, if it's on or near the surface of the moon. 3.52 meters (11.5 feet) per second, if it's on or near the surface of Mars.
The speed reading on the speedometer would increase by approximately 9.8 meters per second for every second the ball falls, assuming it is falling under only the force of gravity. This rate of increase is due to the acceleration of gravity pulling the ball downwards.
At the time the ball is thrown, which is "time 0" the downward speed is 40 m/s.Each second, the downward speed will increase by 9.8 m/s.1. Work out the speed at the end of the first second. This will be 49.8 m/s.2. Then work out how many meters it would have gone in the first second.3. Now work out the ball's height. This is the height at "time 1".4. Draw the ball at time 0 and time 1 on a sheet of paper to help you think.Now, repeat steps 1-4 until the ball's height is close to 0 or goes past 0. Your current "time X" will tell you how many seconds went by for it to get that far.