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None because without an equality sign the given terms can't be considered to be an equation.
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What is the range of the equation y 8x2 - 10?
Without an equality sign the given terms can't be considered to be an equation
How do you identify the polynominal by name and degree of -8x2 -2x 8?
-8x2 - 2x + 8 this is a quadratic equation or a second order polynomial it is a second order polynomial because it has a term in x2 For every polynomial we name it according to the highest power term in the equation.......
Solve x3 plus 7x equals 8x2?
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
8x2 minus 13x minus 6?
(8x2)-(13x-16)= -78
How do you add quadratic equations?
You add compatible terms together. For example, if one equation has 3x2, and the other has 5x2, you combine those two terms as 8x2.
What are the factors of this quadratic equation 8x2 plus 2x -1?
8x2 + 2x - 1 = 8x2 + 4x - 2x - 1 = 4x(2x + 1) - 1(2x + 1) = (4x - 1)(2x + 1)
What is the range of the equation y 8x2 - 10?
Without an equality sign the given terms can't be considered to be an equation
Solve the equation by factoring 15 equals 8x2-14x?
15 = 8x2 - 14x; whence, 8x2 - 14x - 15 = (2x - 5)(4x + 3) = 0. Therefore, x = 5/2 or -3/4.
What is the solution set of the quadratic equation 8x2 plus 2x plus 1 0?
There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 ± 0.330719*i where i is the imaginary square root of -1.
How do you identify the polynominal by name and degree of -8x2 -2x 8?
-8x2 - 2x + 8 this is a quadratic equation or a second order polynomial it is a second order polynomial because it has a term in x2 For every polynomial we name it according to the highest power term in the equation.......
How many real number solutions does the equation -8x2-8x-2 equals 0 have?
Divide all terms by -2: 4x2+4x+1 = 0 (2x+1)(2x+1) = 0 x = -1/2 and also x = -1/2 The quadratic equation has 2 equal roots.
How do you get the product 16 with the numbers 2 3 5 and 8?
You can multiply 8x2 or if you can put addition into the equation you can do (3+5)x2! If you need proof here it is 8x2 can be shown as 8+8 Which equals 16.
Solve x3 plus 7x equals 8x2?
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
What is the discriminant of this equation 8x2 plus 5x plus 6 equals 0?
It is: 25-4(8*6) = -167
What does 8x2 equal?
8x2 is 16 or 16/2=8
What does 5-8x2-5x2 equal?
5-8x2-5x2 is equal to -21.
What two facts can you double to find 8 x 4?
8x2 8x2
