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Q: What are the factors of this quadratic equation 8x2 plus 2x -1?

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There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 Â± 0.330719*i where i is the imaginary square root of -1.

What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).

(4x + 3)(2x - 1) so x = -0.75 or 0.5

It is -8x2

8x2= 16 16-2xy=14xy 14xy-3y(2)= 11x 11xX2= 22x Answer - 22x............... Happy Birthday ! (;

Related questions

(4x - 3)(2x + 3)

8x2 + 6x - 9 = (2x + 3)*(4x - 3)

8x2 + 2x - 1 = (4x - 1)(2x + 1).

There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 Â± 0.330719*i where i is the imaginary square root of -1.

(-2)2-4*8*8 = -252 The discriminant is less than zero so there's no solution to the quadratic equation.

What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).

-4x2 - 32x + x + 8 = 8x2 - 56x : simplify and group the various terms-32x + 56x + x + 8 = 8x2 + 4x225x + 8 = 12x2 : Now present this as a standard quadratic equation.12x2 - 25x - 8 = 0 : Solving for the roots of a quadratic equation gives :-x = [25 ± √(252 + 4x12x8)] ÷ 2x12 = [25 ± √1009] ÷ 24 = [25 ± 31.765] ÷ 24x = 56.765/24 = 2.365 and x = -6.765/24 = -0.282x = 2.365 and -0.282

They are: (4x-5)(2x+5)

-8x2 - 2x + 8 this is a quadratic equation or a second order polynomial it is a second order polynomial because it has a term in x2 For every polynomial we name it according to the highest power term in the equation.......

You add compatible terms together. For example, if one equation has 3x2, and the other has 5x2, you combine those two terms as 8x2.

(x2 + 4 - 2sqrt(3)) (x2 + 4 + 2sqrt(3))

It is: 25-4(8*6) = -167

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