8x2 + 2x - 1
= 8x2 + 4x - 2x - 1
= 4x(2x + 1) - 1(2x + 1)
= (4x - 1)(2x + 1)
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There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 ± 0.330719*i where i is the imaginary square root of -1.
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
(4x + 3)(2x - 1) so x = -0.75 or 0.5
8x2= 16 16-2xy=14xy 14xy-3y(2)= 11x 11xX2= 22x Answer - 22x............... Happy Birthday ! (;
(8x2) + (11x2) = 40