There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 ± 0.330719*i where i is the imaginary square root of -1.
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
(4x + 3)(2x - 1) so x = -0.75 or 0.5
8x2= 16 16-2xy=14xy 14xy-3y(2)= 11x 11xX2= 22x Answer - 22x............... Happy Birthday ! (;
(8x2) + (11x2) = 40
(4x - 3)(2x + 3)
There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 ± 0.330719*i where i is the imaginary square root of -1.
-4x2 - 32x + x + 8 = 8x2 - 56x : simplify and group the various terms-32x + 56x + x + 8 = 8x2 + 4x225x + 8 = 12x2 : Now present this as a standard quadratic equation.12x2 - 25x - 8 = 0 : Solving for the roots of a quadratic equation gives :-x = [25 ± √(252 + 4x12x8)] ÷ 2x12 = [25 ± √1009] ÷ 24 = [25 ± 31.765] ÷ 24x = 56.765/24 = 2.365 and x = -6.765/24 = -0.282x = 2.365 and -0.282
(-2)2-4*8*8 = -252 The discriminant is less than zero so there's no solution to the quadratic equation.
-8x2 - 2x + 8 this is a quadratic equation or a second order polynomial it is a second order polynomial because it has a term in x2 For every polynomial we name it according to the highest power term in the equation.......
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
They are: (4x-5)(2x+5)
You add compatible terms together. For example, if one equation has 3x2, and the other has 5x2, you combine those two terms as 8x2.
It is: 25-4(8*6) = -167
(x2 + 4 - 2sqrt(3)) (x2 + 4 + 2sqrt(3))
8x2 + 16x + 8 = 0
Do you mean 8x2+12x+28?? If so, plug 8,12, and 28 into a,b, and c of this website http://www.math-booster.com/calculators/quadratic-formula.html the answer is imaginary or No Solution