the sum of six and one becuase that equals 7 and the product of six and one equals 6
i think 1
No, you cannot always find the sum of the factors of a product just by knowing the product itself. For example, the product 6 can be factored into 2 and 3, which sum to 5. However, it can also be factored into 1 and 6, which sum to 7. Therefore, the sum of the factors varies depending on the specific factorization chosen.
It is: 6-5 = 1
The product of 6 and 6 is 36 (6 × 6 = 36), and the sum of 6 and 6 is 12 (6 + 6 = 12). When you divide the product by the sum, you calculate 36 ÷ 12, which equals 3. Therefore, the quotient is 3.
Number is 6 1X2X3= 6 1+2+3= 6
6 and -1
i think 1
6 & 1. 6+1=7 and 6X1=6
six, seven 7 + 6 = 13 (sum) 7 - 6 = 1 (difference) 7 x 6 = 42 (product)
29.
product means multiplication sum means adding. 6 * 5 = 30 6 + 5 = 11
Numbers that have a product of 8 are 1,8 and 2,4. Their sums are 9 and 6 respectively. Numbers that have a product of 7 and a sum of 8 are 1 and 7.
It depends on the sum of 6 and WHAT!
The sum of 12 and a product of 11 can be calculated by first finding the product of 12 and 11, which equals 132. Then, adding 12 to this product gives a sum of 144. Mathematically, this can be represented as 12 + (12 x 11) = 12 + 132 = 144.
It is: 6-5 = 1
There may be a formula for solving this sort of problem, but I think it might be best to use trial and error. Start by listing the factors of the product, and then see if the addition of any pair of those give the sum. The factors of 6 are 1, 2, 3 and 6 Of those, only 2 and 3 sum to 5. (1 and 6 sum to 5 in the 1 is negative, but then the product would also be negative, and we were given a positive product.) So the answer is 2 and 3
9(6 + x) = 1