9(6 + x) = 1
9(6+x)=1
9(6+x)=1
6
To calculate the sum of the numbers 1 to n, the formula is: sum = n(1 + n) / 2 So, an equation to find the sum of the integers 1 to 2010 is: sum = 2010 x (1 + 2010) / 2
The sum is 1 and the product is 0.24
The product of a sum and a difference with 31 times 29 is:(30+1) x (30-1)sum to differencemakea product= 30² - 1²= 900 - 1= 899
4 and -1 have a product of -4 and a sum of 3.
0.5
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
Equation one: x + y = 20 Equation two: xy = 5 Equation one divided by equation two: 1/y + 1/x = 4
17x+(1+x)
To calculate the sum of the numbers 1 to n, the formula is: sum = n(1 + n) / 2 So, an equation to find the sum of the integers 1 to 2010 is: sum = 2010 x (1 + 2010) / 2
There's no product or sum until you have at least two numbers.
The sum is 1 and the product is 0.24
The product of a sum and a difference with 31 times 29 is:(30+1) x (30-1)sum to differencemakea product= 30² - 1²= 900 - 1= 899
It is a statement that is equivalent to the equation:(2n+1)*(2n+3) = (2n+1)+(2n+3) + 23.
No, the product of reciprocals is 1.
4 and -1 have a product of -4 and a sum of 3.
y = 1+1+1+1+1+1+1
1.) Identify the names of the reactants and the product, and write a word equation. 2.) Write a formula equation by substituting correct formulas for the names of the reactants and the products. 3.) Balancing the formula equation according to the law of conservation of mass. 4.) Count atoms to be sure that the equation is balanced.