num1 <<= 1; /* shift left */
Using a calculator will make it easier
You multiply the number together - using a calculator if needed.
add the number how many times it says
Apart from using a calculator, specifically if you multiply a whole number by a power of 10:* To multiply a whole number by 10, add a zero to the whole number. * To multiply a whole number by 100, add two zeros to the whole number. * Etc.
20
//lets assume a = 10; b = 20; a = a^b; b = a^b; a = a^b;
You can multiply by using what other number that you use to multiply.
Yes.
Compare the first two numbers with the ternary operator. Store the result in a temporary variable. Compare the temporary variable with the third number, again using the ternary operator.
Using algebra the number works out as 25
Though Java, unlike other languages, does not allow you to directly access the core, memory addresses and system variables, it does have binary operators, such as the shifters >>, <<, and the bitwise operators, |, &, ^. Using these operators, ALL calculations in the computer can be done, even your complicated trig functions. Though options are limited in Java, it does provide a simulated access to low level operations. The bitwise operators are in the link below. Look at the link below to see how the computer really does math.
When using the modulo operator in mathematics or programming, there is a restriction that the divisor (the number after the modulo operator) should be non-zero. A zero divisor would result in a division by zero error, which is undefined.
With repeated multiplication.
The bitwise complement or one's complement operator (~) is used to switch the state of all the bits in a value. Thus 1's become 0, and 0's become 1. One of its many uses is to unset individual bit(s) in a bitmap. We do this with a bitwise AND of the bitmap and the bitwise complement of the bit(s) we want to unset. Original bitmap: 01011100 Bit to unset: 00000100 (e.g., bit 2 (bits are zero based from right)) // Using one's complement and bitwise AND ~00000100 & 01011100 11111011 (one's complement of bit 2) & 01011100 (original bitmap) = 01011000 (original bitmap with bit 2 unset) Note that this formula works even if bit 2 were already unset: 11111011 (one's complement of bit 2) & 01011000 (original bitmap, with bit 2 unset) = 01011000 (original bitmap unchanged)
Multiply the whole number times the numerator. Divide the product by the denominator.
Using a calculator will make it easier
No.