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What is the equation of the line that has a slope of 4 and passes through the point 3-10?
The equation is: y = 4x-22
What is the equation for a line that passes through the points (2-2) and (-422)?
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
What is the equation for the line written in slope-intercept form is parallel to the equation y-22(x-3) and passes through the point (3-3)?
The given expression is not an equation because it has no equality sign but for a line to be parallel to another line they both will have the same slope but with different y intercepts
What is the standard form of a line passing through (-24) and (35)?
If you mean points of (-2, 4) and (3, 5) then its equation works out as 5y = x+22
What is the slope of the line given by the equation y5x-22?
27
What is the equation of the line that has a slope of 4 and passes through the point 4 -6?
m = 4(4, - 6)Use this point slope form.Y - Y1 = m(X - X1)Y - (- 6) = 4(X - 4)Y + 6 = 4X - 16Y = 4X - 22==========equation of the line
-3y equals -7x plus 22?
Is an equation of a straight line, with slope 7/3 x-intercept of 22/7 and y-intercept of -22/3
What is the slope of the line given by the equation y plus 5 equals -22x plus 2?
22
What is the exponential form for 22?
22 = 21*111 = 2*11
What is the line passes through the points (22-3)and (-1214)?
To find the equation of the line that passes through the points (22, -3) and (-12, 14), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the given points, we get ( m = \frac{14 - (-3)}{-12 - 22} = \frac{17}{-34} = -\frac{1}{2} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, we can write the equation as ( y + 3 = -\frac{1}{2}(x - 22) ), which simplifies to ( y = -\frac{1}{2}x + 4 ).
How do you write an equation of the line in standard form with integer coefficients the line through -22 and 1-4?
To write the equation of the line in standard form (Ax + By = C) with integer coefficients, first find the slope (m) using the points (-22, 1) and (1, -4). The slope is calculated as ( m = \frac{-4 - 1}{1 - (-22)} = \frac{-5}{23} ). Next, use the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, say (1, -4), to get ( y + 4 = -\frac{5}{23}(x - 1) ). Rearranging this equation to standard form results in ( 5x + 23y = -83 ).
What slope-intercept form of the equation of a line that goes through (22) and is parallel to yx 7?
To find the slope-intercept form of the equation of a line that goes through the point (2, 2) and is parallel to the line ( y = x + 7 ), we first identify the slope of the given line, which is 1. Since parallel lines have the same slope, the new line will also have a slope of 1. Using the point-slope form ( y - y_1 = m(x - x_1) ) with ( m = 1 ) and the point (2, 2), we can rewrite it as ( y - 2 = 1(x - 2) ), which simplifies to ( y = x ).
