The line goes through two numbers, so it can only be the 1-dimensional number line.
The equation is: y = 4x-22
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The given expression is not an equation because it has no equality sign but for a line to be parallel to another line they both will have the same slope but with different y intercepts
If you mean points of (-2, 4) and (3, 5) then its equation works out as 5y = x+22
27
m = 4(4, - 6)Use this point slope form.Y - Y1 = m(X - X1)Y - (- 6) = 4(X - 4)Y + 6 = 4X - 16Y = 4X - 22==========equation of the line
Is an equation of a straight line, with slope 7/3 x-intercept of 22/7 and y-intercept of -22/3
22
22 = 21*111 = 2*11
To find the equation of the line that passes through the points (22, -3) and (-12, 14), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the given points, we get ( m = \frac{14 - (-3)}{-12 - 22} = \frac{17}{-34} = -\frac{1}{2} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, we can write the equation as ( y + 3 = -\frac{1}{2}(x - 22) ), which simplifies to ( y = -\frac{1}{2}x + 4 ).
To write the equation of the line in standard form (Ax + By = C) with integer coefficients, first find the slope (m) using the points (-22, 1) and (1, -4). The slope is calculated as ( m = \frac{-4 - 1}{1 - (-22)} = \frac{-5}{23} ). Next, use the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, say (1, -4), to get ( y + 4 = -\frac{5}{23}(x - 1) ). Rearranging this equation to standard form results in ( 5x + 23y = -83 ).
If 2x = 22 Then x = Log2 22