If you mean points of (-2, 4) and (3, 5) then its equation works out as 5y = x+22
what is the horizontal line that passes through (-5,6)
There is no name for it except "A line perpendicular to a line segment and passing through its midpoint".
(3,1)(3,2)
find the slop of the line passing through (1,5) and (0,2)
If the line passing through these points is a straight line then it has a positive gradient.
what is the horizontal line that passes through (-5,6)
There is no name for it except "A line perpendicular to a line segment and passing through its midpoint".
The slope of a vertical line is undefined and so there cannot be a slope-intercept form of the equation.
What is the equation of the vertical line passing through (-5,-2)
(3,1)(3,2)
find the slop of the line passing through (1,5) and (0,2)
The equation of a vertical line passing through the point (a, b) is x a.
If the line passing through these points is a straight line then it has a positive gradient.
The equation in slope-intercept form would be y=-2x
The standard form is: 5x - y + 4 = 0
The general form is 11x - 10y + 19 = 0
Points: (4, 1) and (5, 2) Slope: 1 Equation: y = x-3 Equation in its general form: x-y-3 = 0