(x-2)(x+12) = 0
x = 2 or x -12
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
It is a linear equation in x. 10x = 7x + 15 3x = 15 x = 5
This simplifies to x2 + 10x + 17 = 0 which has no solution in integers. Quadratic formula gives roots as -2.17 and -7.83 to the nearest hundredth. If the original equation had been "equals 0" rather than "equals 8", there would have been only one root: x = -5
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Solving the discriminant: k = -2
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
y=-10x-4
10x - 78 = 1, 10x = 79, x = 7.9
x=-8
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
It is a linear equation in x. 10x = 7x + 15 3x = 15 x = 5
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
This simplifies to x2 + 10x + 17 = 0 which has no solution in integers. Quadratic formula gives roots as -2.17 and -7.83 to the nearest hundredth. If the original equation had been "equals 0" rather than "equals 8", there would have been only one root: x = -5
When x = -5
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
Using the quadratic equation formula: x = -5-/+ the square root of 7
You never square a whole equation. That's just silly.