12x-3=2x+17 10x-3=17 10x=20 x=2
Factorising, we have, 9x2+ 30x + 25 = (3x + 5)2;thus, when y = 0, x = -1⅔. This tells us that the sole x-intercept of this function is at the vertex, (0, 1⅔).
12x + 9 = 10x + 1 Subtract 10x from both sides: 2x + 9 = 1 Sutract 9 from both sides: 2x = - 8 Divide both sides by 2: x = -4
X2 + 10X - 13 = 17 add 13 to each side X2 + 10X = 30 halve the linear coefficient ( 10 ), square it and add it to both sides X2 + 10X + 25 = 30 + 25 factor on the left and gather terms on the right (X + 5)2 = 55 (X + 5)2 - 55 = 0 ---------------------------vertex form, (- 5, - 55 ), is the vertex -------------------------------------------[-------------------------------]
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
It is 4x^2 + 10x - 1
9x2 - 28x + 20 = 9x2 - 18x - 10x + 20 = 9x(x - 2) - 10(x - 2) = (9x - 10)*(x - 2)
It is: 122-4*(9*-2) = 216
9x2 + 7x = 2 9x2 + 7x - 2 = 0 9x2 + 9x - 2x - 2 = 0 9x(x + 1) - 2(x + 1) = 0 (9x - 2)(x + 1) = 0 x ∈ {-1, 2/9}
I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43
6-3x = 5x-10x+2 4 = 8x-10x 4 = -2x x = -2
10x. 'coz x=? so just add 2 & 8.
10x + 2 - 62 Subtract '2' from both sides 10x = 60 Divide both sides by '10'/ x = 6 The answer!!!!!
-2-5
12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4
7x + 8 = 10x - 2 ∴ 3x = 10 ∴ x = 10/3
Though 10x +24 is an expression and it can not be evaluate, we can write 10x+24=2 • (5x + 12)