This simplifies to x2 + 10x + 17 = 0 which has no solution in integers. Quadratic formula gives roots as -2.17 and -7.83 to the nearest hundredth.
If the original equation had been "equals 0" rather than "equals 8", there would have been only one root: x = -5
They intersect at the point of: (-3/2, 11/4)
That depends what the value of x is.
x^2 + 10x + 16 = (x + 8)(x + 2)
If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5
(x + 5)(x + 5)
They intersect at the point of: (-3/2, 11/4)
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
x2 + 9x2 = 10x2
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
3x2 + 10x + 3 = (x + 3)(3x + 1).
That depends what the value of x is.
x^2 + 10x + 16 = (x + 8)(x + 2)
X2 + 10X - 11 = 0What two factors of - 11 add up to 10 ?(X - 1)(X + 11)==========X = 1X = - 11
If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2
X2 + 10X - 13 = 17 add 13 to each side X2 + 10X = 30 halve the linear coefficient ( 10 ), square it and add it to both sides X2 + 10X + 25 = 30 + 25 factor on the left and gather terms on the right (X + 5)2 = 55 (X + 5)2 - 55 = 0 ---------------------------vertex form, (- 5, - 55 ), is the vertex -------------------------------------------[-------------------------------]