This simplifies to x2 + 10x + 17 = 0 which has no solution in integers. Quadratic formula gives roots as -2.17 and -7.83 to the nearest hundredth.
If the original equation had been "equals 0" rather than "equals 8", there would have been only one root: x = -5
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They intersect at the point of: (-3/2, 11/4)
That depends what the value of x is.
x^2 + 10x + 16 = (x + 8)(x + 2)
If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3