Slope of a line perpendicular to x-y=16
10 is.
negative 1
0909
Equation of line: y = x+5 Equation of circle: x^2 +4x +y^2 -18y +59 = 0 The line intersects the circle at: (-1, 4) and (3, 8) Midpoint of line (1, 6) Slope of line: 1 Perpendicular slope: -1 Perpendicular bisector equation: y-6 = -1(x-1) => y = -x+7 Perpendicular bisector equation in its general form: x+y-7 = 0
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
x-3y+2 = 4 -3y = -x+4-2 -3y = -x+2 y = 1/3x-2/3 Slope or gradient of the perpendicular line is -3 Use y-y1 = -3(x-x1) to find the perpendicular equation
One single line is never parallel or perpendicular. Those words tell you somethingabout the relationship between two lines.
line in data is y=-2X+6 The perpendicular line will have a slope of = +1/2 Note : m X m' = -1 , m= slope of line 1 ; m'= slope of perpendicular line to line 1
It is not one, but they are two perpendicular lines.
3
The second equation works out as y = -1/2x+6 therefore it is perpendicular