what is the slope of the line that has the equation 4x+2y=12?
Slope of a line = m slope of perpendicular line = -1/m
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
The slope of a line perpendicular to one with a slope of m is -1/m.
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
The slope is -0.2
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
It is: 1/5
It is: -1/2
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
It is -1/2
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3