There's a trick you can use: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. Here 2+4+5+2 = 13. Is 13 divisible by 3? You decide.
The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.
78 is evenly divisible by 1, 2, 3, and 13.
All of the multiples of 78 are. There are an infinite number of them.
13 is one such number.
2+3+2+6=13 which is not divisible by 3 thus 2326 is not divisible by 3
No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
No. Consider 13 or 23.
It is divisible by 6
Any number that is divisible by both 2 and 3 is divisible by 6.
14