Q: Which number is divisible by 2 3 and 13?

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The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.

There's a trick you can use: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. Here 2+4+5+2 = 13. Is 13 divisible by 3? You decide.

78 is evenly divisible by 1, 2, 3, and 13.

All of the multiples of 78 are. There are an infinite number of them.

14

Not evenly. 585 is divisible by 3, 5, and 13.

2+3+2+6=13 which is not divisible by 3 thus 2326 is not divisible by 3

Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.

No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder

13 is one such number.

No. Consider 13 or 23.

102 is divisible by 2,3 and 6 A number is divisible by 2 if the number has even number on its unit place. A number is divisible by 3 if the sum of all the digits of the number is divisible by 3. For example= In number 102 1+0+2=3 and yes it is divisible by 3 A number is divisible by 6 if it is divisible by both 2 and 3 These laws of divisibility are applicable everywhere.

It is divisible by 6

There is no such number.

Any number that is divisible by both 2 and 3 is divisible by 6.

To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3â†’ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3â†’ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3â†’ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3â†’ 121 is not divisible by either 2 or 3, so it is not divisible by 6

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.

starting with the first prime number (2), setting the result to 78check if the current result is divisible by the current primeif it does not divide repeat from step 2 with the next prime numbermake a note of the prime numberdivide the current result by the current prime number and make the result the current resultif current result is not 1 repeat from step 2The list of primes noted in step 4 form the prime factorisation.1. current prime = 2, current result = 782. 78 is divisible by 23. current result is divisible4. Note: 25. 78 ÷ 2 = 39 → current result6. current result not 1, repeat from step 22. 39 is not divisible by 23. set current prime to 3, repeat from step 22. 39 is divisible by 33. current result is divisible4. Note: 35. 39 ÷ 3 = 13 → current result6. current result not 1, repeat from 22. 13 not divisible by 33. next prime (5) → current prime2. 13 not divisible by 53. next prime (7) → current prime2. 13 not divisible by 73. next prime (11) → current prime2. 13 not divisible by 113. next prime (13) → current prime2. 13 divisible by 133. current result is divisible4. Note: 135. 13 ÷ 13 = 1 → current result6. current result is 17. factorisation of 78 is 2 x 3 x 13.

A number is divisible by 2 if that number is an even number, which means it ends in 0, 2, 4, 6, or 8. A number is divisible by 3 if the sum of its digits is evenly divisible by 3.

2 and 3Today, people don't explain why a number has to be divisible by 2 and 3 to be divisible by 6 or how it works.

Numbers are divisible by 6 if they are divisible by both 2 and 3.All even numbers are divisible by 2. Odd numbers are not.To see if a number is divisible by 3, add the individual digits of the number to each other and see if that number is divisible by 3. If it is, then the original number is also divisible by 3.Example: 2712, add 2+7+1+2=12 Is 12 divisible by 3? Yes. Therefore, 2712 is divisible by 3.The number 2712 is also divisible by 2, since it is an even number.Now you know that 2712 is divisible by 6.

For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.

If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.

The Answer :)If the number is divisible by 2andIf the number is divisible by 3To find out if the number is divisible by 2 you look at the last digit of the number and see if it's an even number...ex: 420 you look at the 0 and 0 is a even number so 420 is divisible by 2.To find out if a number is divisible by 3 you add all the digits together and then see if the sum is divisible by 3...ex: 420 you add 4+2+0= 6 . and 6 is divisible by 3 so the number 420 is divisible by 3.yeah!

3411 is an odd number and is not divisible by 2. but, it is divisible by 3. 3411/3 = 1137