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Q: Which number is greater than the square root of 3 and less than 1.9?

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when the number is greater than 1

Yes, if the number is less than 1

Yes, if the number is less than '1'.Just the opposite, if the number is greater than '1'.

No there is not. If you are looking for prime factors of a number and you get to the square root of that number you can stop. Yes, there is. If an integer is not itself a prime, then one of its factors will be less or equal to its square root and the "co-factor" will be greater than or equal to the square root. But both cannot be greater than the square root so, when searching for factors, you can stop when you reach the square root.

a square number is a number that you multiply the same number like:8.8 = 64 get it

It is greater because the square root of 65 is 8.06.

Actually it can, if it's not the square of a prime number. For example, 144 is the square of 12; but you can also factor it as 6 x 24.

greater than

Since the square root of a number is the "number times itself that equals the original number," it makes sense that the larger the original number, then the larger the square root. The value of the square root of 2 will be greater than the value of the square root of 1.5.

greater than

√3 = 1.732050808 Therefore, 0.85 is less than the square root of 3.

only if x is greater than 1

x can be any number greater than 16 and less than 81.

greater than

No. The square roots of numbers between 0 and 1 (not including 0) are greater than or equal to (in the case of 1) the number. The square root of 0.49 is 0.7 for example.

It is if the number is more than ' 1 '. If the number is less than ' 1 ', then it's smaller than its own square root.

You try dividing it by all prime numbers less than of equal to its square root.

No, not always since: if a number is more than 1, then its square root is smaller than the number. if a number is less than 1, then its square root is bigger than the number.

The width can be any number greater than zero and less than the square root of 35, and the length can be any number greater than the square root of 35, subject to the constraint that the product of the length and the width must be 35.

the square root of 10

No.

Yes. The square root of 64 is 8 and the square root of 81 is 9, so the square root of 69 has to be greater than 8 and and less than 9.

The square root of the number acts sort of like the 'multiplicative middle' of the number. When you multiple the square root by itself, you get back to original number. When you search for factors of the number (easier to see when thinking of real numbers) it's intuitive that you must have one number on either side of this 'multiplicative middle'

The square root of 625 is 25, and 2 less than 25 is 23.

when x is a negative number --- is a wrong answer since square root of a negative number is not defined. So x has to be zero or a positive number. The correct answer is that when x lies between 0 and 1 (with both limits excluded), its square root is greater than the number itself. Of course at both limits, the square root (assuming the positive square root - since a square root of a number can be positive or negative, both with the same absolute value) is the same as the number.